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tino4ka555 [31]
3 years ago
10

A rectangle has a length 1 foot longer than twice the width. The area of the rectangle is 253 square feet. Find the (a) length a

nd the (b) width​
Mathematics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

length of a rectangle is 1 foot more than twice the width

Let x and (2x+1)represent the width and length respectively

P = 2x + 2(2x+1) = 20ft

 6x = 18ft

 x = 3ft, the width.  the length is 7ft    (2*3+1)

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Step-by-step explanation:

The least common multiple is a number that both numbers can multiply something to get to, and the smallest possible common one.

Let's try listing out the multiples of 2:

2, 4, 6, 8, 10, 12, 14, 16, 18, 20

And the multiples of 7:

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Notice that both have the number 14 in common, and it is the first number that they do so.  There are lots of other multiples that they have in common too, but 14 is the least.

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Please find which quadratic equation matches the graph with work attached
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C

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Next we can use the equation x=\frac{-b}{2a} that is used in order to find the vertex of the parabola.

A)

f(x)=-x^2+6x+7\\a=-1,b=6,c=7\\\\x=\frac{-6}{-2} \\x=3

As the vertex is at x=3 on the graph, this one could be a contender.

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This rules option D out.

For this last step, we can look at where the zeroes would be for each equation. (These values are irrational, so we cannot look at specific number)

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f(x)=-(x^2-6x-7)

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