Step-by-step explanation:
Use the quadratic formula to find the solutions.
−b±√b2−4(ac)2a-b±b2-4(ac)2a
Substitute the values a=9a=9, b=0b=0, and c=−81c=-81 into the quadratic formula and solve for xx.
x=±3x=±3
The final answer is the combination of both solutions.
x=3,−3x=3,-3
X = 3
y = 5
(3,5)
I used substitution because It seemed the easiest.
From the second equation I isolated it for Y to get y=20-5x
I plugged this in to the other equation for the Y value to perform substitution.
-7x + 8 (20-5x) = 19
then it's simple algebra
-7× + 160 - 40x = 19
-47x + 160 = 19
subtract 160 from both side and divide both side by -47 to isolate x.
-47x = -141
x=3
then to find Y, simple plug this into one of the equation above. or simply use this one that we already isolated for Y:
y=20-5x
y=20-5 (3)
y=5
hope that helps
Answer:
- After a 90% increase, there is 2,280
- After a 55% increase, there is 2015
- After a 58% decrease, there is 588
Step-by-step explanation:
Assume the original figures are x.
After a 90% increase, there is 2,280:
x * (1 + 90%) = 2,280
1.9x = 2,280
x = 2,280 / 1.9
= 1,200
After a 58% decrease, there is 588:
x * (1 - 58%) = 588
0.42x = 588
x = 588/0.42
x = 1,400
After a 55% increase, there is 2,015:
x * (1 + 55%) = 2,015
1.55x = 2,015
x = 2,015/1.55
x= 1,300
Order:
1,200 ⇒ 1,300 ⇒ 1,400
The area of a trapezoid is (¹/₂) (height) (base-1 + base-2)
A). Area = (¹/₂) (1¹/₂) (6 + 3¹/₂) = (¹/₂) (³/₂) (¹⁹/₂) = ⁵⁷/₈ = 7¹/₈
B). Area = (¹/₂) (1¹/₂) (2 + 3¹/₂) = (¹/₂) (³/₂) (¹¹/₂) = ³³/₈ = <em>4¹/₈ <===</em>
C). Area = (¹/₂) (3) (2 + 3¹/₂) = (¹/₂) (⁶/₂) (¹¹/₂) = ⁶⁶/₈ = 8¹/₄
D). Area = (¹/₂) (1¹/₂) (2 + 7) = (¹/₂) (³/₂) (¹⁸/₂) = ⁵⁴/₈ = 6³/₄
Answer:
The area of this semicircle would be about 14.14 (14.1372) ft squared.
Step-by-step explanation:
Formula is A = (1/2) * π * r 2.
