Explanation:
To understand how this program is working let us print the variable value at different stages of the program so that we can understand how it is working.
Intitally, value=10 when it was declared.
Then we added 5 and it become value=15
then we used fork() function which creates a parent(orignal) and child(duplicate)
When fork() succeeds it returns the child pid to parent and returns 0 to the child. As you can see (pid > 0) condition is always true therefore the parent pid value becomes 35 ( 15+20) and the child pid value becomes 0.
#include <stdio.h>
#include <unistd.h>
int main( ) {
int value = 10;
printf("%d\n",value);
int pid;
value += 5;
printf("%d\n",value);
pid = fork( );
printf("%d\n",pid);
if (pid > 0 )
{
value += 20;
}
printf("%d\n",value);
return 0;
}
Output:
10 (initial value)
15 (modified value)
5343 (pid when fork is used)
35 (final modified value)
0 (child value)
15 (the parent value when fork was used)
Answer:
Zynga
Explanation:
Zynga is a leading developer of the world’s most popular social games that are played by millions of people around the world each day.
The simplified equation is given as Y=A_3A0+A3A0. To draw the circuit diagram using a minimum number of gates we use this equation and the x^2 equation to form the truth table. This is further explained below.
<h3>What is a circuit?</h3>
Generally, a circuit is simply defined as a full circular channel via which electricity travels in electronics. A power flow, terminals, and a drain make up a basic circuit.
In conclusion, The circuit will need 4 inputs to produce 16 combinations in order to determine if the month contains 31 days. At 4 inputs, there are 12 inputs required. the
Hence,we use this information and the x^2 equation to form the truth table
the Equation is given as
Y=A_3A0+A3A0
Read more about circuit
brainly.com/question/27206933
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Refraction represents a change in the direction of propagation when beams of light encounter a medium with a different density.
Reflection is the return of light to the medium it came from when it encounters a mirror.
<u>Answer:</u>
<em>int fNumber,scndNumber = -1, </em>
<em>dup = 0;
</em>
<em>do {
</em>
<em>cin >> fNumber;
</em>
<em>if ( scndNumber == -1) {
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>else {
</em>
<em>if ( scndNumber == fNumber )
</em>
<em>duplicates++;
</em>
<em>else
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>} while(fNumber > 0 ); </em>
<em>cout << dup;
</em>
<u>Explanation:</u>
Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>
<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.
