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IceJOKER [234]
2 years ago
13

What is the process to find the product of 6x107 for 5th grade

Mathematics
1 answer:
siniylev [52]2 years ago
7 0
Line it up vertically...
107
<u>    6</u>

...then multiply 7 by 6, and carry the 4:
107<u>
    6</u>
    2

Then multiply the 0 by 6 and add the carried 4 to the product of the 0 and 6:
107
<u>    6</u>
   42

Then multiply 1 by 6:
107
<u>    6</u>
642
<u />
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solong [7]
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You are making a scale drawing with a scale of 2 in. = 17 ft. Explain how you find the length of the drawing of an object that h
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Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
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