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2 years ago

Which numbers are divisible by 5? You must select ALL the correct answers to get credit for this question. 42 17 50 15

Mathematics

2 answers:

Bess [88]2 years ago

5 0

Answer:

50 & 15.

Step-by-step explanation:

50/5=25

15/5=3

Alex Ar [27]2 years ago

3 0

Answer:

50, 15

Step-by-step explanation:

All numbers, which end in 0 or 5, except for 0 itself, are divisible by 5

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a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and

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Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

$x(t) = -4.9t^{2} + 9.8t$

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format $x(t) = at^{2} + bt + c$

The vertex is the point $(t_{v}, x(t_{v}))$ , in which

$t_{v} = -\frac{b}{2a}$

In this question:

$x(t) = -4.9t^{2} + 9.8t$

So $a = -4.9, b = 9.8$

Vertex:

$t_{v} = -\frac{9.8}{2*(-4.9)} = 1$

The time taken for the upward motion is 1 second.

$x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9$

It reaches a maximum height of 4.9 meters.

Downward motion:

From the vertex to the ground.

The ground is t when x = 0. So

$-4.9t^{2} + 9.8t = 0$

$4.9t^{2} - 9.8t = 0$

$4.9t(t - 2) = 0$

$4.9t = 0$

$t = 0$

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It reaches the ground when t = 2 seconds.

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3 years ago

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gtnhenbr [62]

Answer:

5 years

Step-by-step explanation:

To determine the number of years needed for the company to process a certain amount of milk, we use the given function which relates the number of years, x, and the gallons of milk, y. We simply substitute the number of gallons to y and solve for x.

y = x^6 − 9x^4 + 70x^2

630 = x^6 − 9x^4 + 70x^2

Solving for x, we will have

x = 4.8866 years or approximately 5 years

Hope this answer helps you :)

Have a great day

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