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3 years ago

Please help. thank you.

Mathematics

2 answers:

ruslelena [56]3 years ago

7 0

Answer: 150(1 + 4) 16

Step-by-step explanation: 4 goes in the first box and 16 goes in the little one.

Tresset [83]3 years ago

3 0

Usuageieisbahisisvshriirjdvsvnzkvog

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Gnesinka [82]

It depends, what does a mean? If you know just add what a means to 3 then subtract 4.

4 0

3 years ago

Help Plz (Emergency)

kompoz [17]

Answer: s = 36

Step-by-step explanation: The key to solving multistep equations is isolating the variable. This is why I first subtracted 14 on each side. This left me with 1/3s=12. Then, to isolate "s" even more, I didvided by 1/3 on each side. This gave me s = 36 as an answer.

To divide by a fraction, use "keep change flip." Keep the first mumber, change division to multiplication, and flip the fraction. I included a picture of me doing this.

If you have any other questions, please feel free to ask :)

3 0

4 years ago

What is the standard form for 200,000+80,000+700+6

ozzi

280,706 is the standard form

7 0

3 years ago

In the figure, AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. Prove that △AEB ≅ △DEC

Makovka662 [10]

Answer:

From top to bottom:

A, J, E, B, I, C, D, G, F, H

See below for more clarification.

Step-by-step explanation:

We are given that AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. And we want to prove that ΔAEB ≅ ΔDEC.

Statements:

1) XY is perpendicular to AB.

Definition of perpendicular bisector.

2) XY ⊥ CD.

In a plane, if a transveral is perpendicular to one of the two parallel lines, then it is perpendicular to the other.

3) m∠AXE = 90°, m∠DYE = 90°.

Definition of perpendicular lines.

4) ∠AXE ≅ ∠DYE.

Right angles are congruent.

5) XE ≅ YE

Definition of a midpoint.

6) ∠A ≅ ∠D.

Alternate Interior Angles Theorem

7) ΔAEX ≅ ΔDEY

AAS Triangle Congruence*

(*∠A ≅ ∠D, ∠AXE ≅ ∠DYE, and XE ≅ YE)

8) AE ≅ DE

Corresponding parts of congruent triangles are congruent (CPCTC).

9) ∠AEB ≅ ∠DEC

Vertical Angles Theorem

10) ΔAEB ≅ ΔDEC

ASA Triangle Congruence**

(**∠A ≅ ∠D, AE ≅ DE, and ∠AEB ≅ ∠DEC)

3 0

3 years ago

In isosceles $\triangle abc$ (with $ab = ac$), point $d$ lies on $ab$ such that $cd = cb$. if $\angle adc = 115^\circ$, what is

Nuetrik [128]

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Answer: 15°.

3 0

3 years ago

Read 2 more answers