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AysviL [449]
3 years ago
9

their are 1296in^2 in one square yard. Use a proportion to find out how many square yards of carpet would take over the floor

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0

Answer:

20 11/32 yards

Step-by-step explanation:

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Based on Pythagoras' theorem, explain the structure of the Egyptian pyramids? <br> PLZ HELPPPPP
frutty [35]

The pyramids in Egypt developed in several stages. The first pyramid dates back to the third dynasty. King Djoser had a step pyramid constructed at Saqqara. Djoser's chief architect Imhotep is credited with developing the step pyramid from the older mastaba tomb. The mastaba is thought by some to represent a bed. Mastabas are large rectangular structures that form the monument for the deceased. The dead were buried in shafts that were sunk into the ground. Imhotep stacked successively smaller rectangular shaped structures to create what is now known as the step pyramid.

Miroslav Verner [1]. writes: "At the outset the structure had the form of a square mastaba (stage M1), which was gradually enlarged, first equally on all four sides (stage M2) and then only o the east side (stage M2). The mastaba <...> already had a step shape in the M3 stage. The step-shaped mastaba was finally built in two stages, first as a four step (P1) and then as a six-step (P2) pyramid, which no longer had - and this is a noteworthy point - a square base; it now had a rectangular base, oriented east-west."

4 0
4 years ago
a baker orders 162 eggs. each carton contains 18 eggs. which equation can you use to find the number x of cartons? explain your
ololo11 [35]
18x = 162
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6 0
3 years ago
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Use elimination "subtraction" to solve this system. 2x+y=2 and 5x+y=8​
Alex17521 [72]

Answer:

y= 0 and y = 3

Step-by-step explanation:

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3 years ago
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Find the range of the following piecewise function.
Olegator [25]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Y=-x squared - 6x -5 what is the vertex and x-intercepts
Alenkasestr [34]
y=-x ^2  - 6x -5 \\ \\  standard \  form \\ \\y=ax+bx+c \\ \\V(p,q)\\ \\ p=\frac{-b}{2a}=\frac{-(-6)}{-2}=3\\ \\\Delta = b^{2}-4ac =14^{2}-4*1*(-51)=196+204=400 \\ \\q=\frac{-\Delta }{4a} =\frac{-400}{4}=100\\ \\V( 3,100)\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-14- \sqrt{400}}{2}=\frac{-14-20}{2}= \frac{-34}{2}=-17\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-14+ \sqrt{400}}{2}=\frac{-14+20}{2}= \frac{6}{2}=3
6 0
3 years ago
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