You randomly choose one chess piece. Without replacing the first piece you choose a second piece. Find the probability of choosi
ng the first piece and then the second piece.
8. bishop and Bishop
8. bishop and Bishop
1 answer:
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Answer:
Step-by-step explanation:
Well we can simplify the numerator, by multiplying the 4 by the 6 and the m^3 and m^4 (add the exponents, explained in one of my previous answers I think)
This gives us the fraction:
We can now divide the m^7 by m^2 by subtracting the exponents, and the reason why this works, is you're simply cancelling out the m's, If we express this in expanded form we have the following fraction:
Since there is two m's in the denominator and there is also two (more than two) m's in the numerator, we can cancel those two m's out, and we get the fraction:
which can be simplified in exponent form as:
, now all we have to do is divide the 24 by the 3, to get 8
This gives us the answer:
The correct answer is y=−1/16
