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Vinil7 [7]
3 years ago
8

You randomly choose one chess piece. Without replacing the first piece you choose a second piece. Find the probability of choosi

ng the first piece and then the second piece.
8. bishop and Bishop

Mathematics
1 answer:
Furkat [3]3 years ago
4 0
Total of 16 pieces in the chess which foam our sample space.
Total of 2 pieces of bishop.
If you first chose the bishop then probability =2/16=1/8=0.125
If you again chose the bishop without replacement(total sample space left=15 and 1 piece of bishop left) then probability =1/15=0.0666


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IRISSAK [1]

Step-by-step explanation:

2(x+\frac{3}{4})^2-5=123

1. Add 5 to both sides.

5+2(x+\frac{3}{4})^2-5=123+5

2(x+\frac{3}{4})^2=128

2. Divide both sides by 2.

\frac{2(x+\frac{3}{4})^2 }{2}=\frac{128}{2}

(x+\frac{3}{4} )^2=64

3. Take the square root of both sides.

\sqrt[]{(x+\frac{3}{4})^2 } =\sqrt[]{64}

x+\frac{3}{4}=8

4. Subtract \frac{3}{4} from both sides.

-\frac{3}{4}+x+\frac{3}{4}=8-\frac{3}{4}

x=8-\frac{3}{4}

x=\frac{(8)(4)-3}{4}

x=\frac{32-3}{4}

x=\frac{29}{4}

8 0
3 years ago
Please see attached below. <br> Please explain.
vivado [14]

Answer:

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5 0
4 years ago
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Nesterboy [21]

Answer:

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Also the probability of choosing a $20 bill is

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