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Vinil7 [7]
3 years ago
8

You randomly choose one chess piece. Without replacing the first piece you choose a second piece. Find the probability of choosi

ng the first piece and then the second piece.
8. bishop and Bishop

Mathematics
1 answer:
Furkat [3]3 years ago
4 0
Total of 16 pieces in the chess which foam our sample space.
Total of 2 pieces of bishop.
If you first chose the bishop then probability =2/16=1/8=0.125
If you again chose the bishop without replacement(total sample space left=15 and 1 piece of bishop left) then probability =1/15=0.0666


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Elza [17]

Absolute value of 7. Any real numbers in the absolute sign would equal to the positive value.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u>

\large \boxed{ |x|  =  \begin{cases} x  \:  \:  \:  \: (x \geqslant 0) \\  - x \:  \:  \:  \: (x < 0) \end{cases}}

If we substitute x = 7 in. Answer by using the definition of absolute value. Note that we only substitute x = 7 in x and not -x since 7 is greater than 0 and not less than 0.

\large{ |7|  = 7 \:  \:  \:  \:  (x \geqslant 0)}

You may also be wondering what will happen if we substitute x = any negative numbers.

\large{ | - 7|  =  -  ( - 7) \:  \:  \:  \: (x <  0)} \\  \large \boxed{ | - 7|  =  7}

Because -7 is less than 0. We substitute in -x and not x. This is the definition of absolute value. But to understand it easily, any numbers in absolute value have to equal to their positive value.

Conclusion

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  • |7| is 7.
  • |x| is x when x ≥ 0 but -x when x < 0

Let me know if you have any doubts regarding the absolute value through comment!

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