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gavmur [86]
2 years ago
9

Who invented Maths?????​

Mathematics
2 answers:
olchik [2.2K]2 years ago
8 0
Archimedes is known as the Father of Mathematics. Mathematics is one of the ancient sciences developed in time immemorial.
valentinak56 [21]2 years ago
7 0

Answer:

Archimedes invented Maths.He is known as the Father of Mathematics.

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A circle passes through point (-2, -1) and its center is at (2, -1). Which equation represents the circle?
ludmilkaskok [199]

The choices are missing, but we can solve the problem from the given information

Answer:

The equation which represents the circle is (x - 2)² + (y + 1)² = 16

Step-by-step explanation:

The form of the equation of a circle is (x - h)² + (y - k)² = r², where

  • (h , k) are the coordinates of its center
  • r is the radius of it

∵ The coordinates of the center of the circle are (2 , -1)

∴ h = 2 and k = -1

The radius of the circle is the segment whose join the center of the circle and any point on the edge of the circle

∵ The circle passes through point (-2 , -1)

∴ The radius of the circle is the distance from the center (2 , -1)

    and the point (-2 , -1)

The y-coordinates of the two points are equal that means the radius is a horizontal segment and its length is the difference between their x-coordinates

∵ r = 2 - (-2)

∴ r = 4

Now let us substitute h, k, and r in the form of the equation of the circle

∵ (x - 2)² + (y - -1)² = (4)²

∴ (x - 2)² + (y + 1)² = 16

The equation which represents the circle is  (x - 2)² + (y + 1)² = 16

7 0
3 years ago
Factor 7(h+k)^2-21(h+k)
VARVARA [1.3K]
7(h+k)(h+k- 3) if this is the answer you're looking for this is what  I got so. Good luck
5 0
3 years ago
Jay needs 19 quarts more for outside of barn uses 107 quarts in all how many gal will be used on inside
Jet001 [13]

Answer:

This equation belongs to One variable linear equation  because there is one variable = x and the exponent number is one

solving equations :

x= 44 quarts

3 0
3 years ago
EXAMPLE 5 If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (1, 2, 0) in the
solong [7]

Answer:

<h2>a) f =  sin(yz)i + xzcos(yz)j + xycos(yz)k</h2><h2>b) -2</h2>

Step-by-step explanation:

Given f(x, y, z) = x sin(yz), the formula for calculating the gradient of the function is expressed as ∇f(x, y, z) = fx(x, y, z)i+ fy(x, y, z)j+fz(x, y, z)k where;

fx, fy and fz are the differential of the functions with respect to x, y and z respectively.

a) ∇f(x, y, z) = sin(yz)i + xzcos(yz)j + xycos(yz)k

The gradient of f =  sin(yz)i + xzcos(yz)j + xycos(yz)k

b) Directional derivative of f at (1,2,0) in the direction of v = i + 4j − k is expressed as ∇f(1, 2, 0)*v

∇f(1, 2, 0) = sin(2(0))i +1*0cos(2*0)j + 1*2cos(2*0)k

∇f(1, 2, 0) = sin0i +0cos(0)j + 2cos(0)k

∇f(1, 2, 0) = 0i +0j + 2k

Given v = i + 4j − k

∇f(1, 2, 0)*v (note that this is the dot product of the two vectors)

∇f(1, 2, 0)*v =  (0i +0j + 2k)*(i + 4j − k )

Given i.i = j.j = k.k =1 and i.j=j.i=j.k=k.j=i.k = 0

∇f(1, 2, 0)*v = 0(i.i)+4*0(j.j)+2(-1)k.k

∇f(1, 2, 0)*v = 0(1)+0(1)-2(1)

∇f(1, 2, 0)*v =0+0-2

∇f(1, 2, 0)*v= -2

 

Hence, the directional derivative of f at (1, 2, 0) in the direction of v = i + 4j − k is -2

7 0
3 years ago
What is an equation of the the line that passes through the point (3,6)and is parallel to the line 4x-3y=21
disa [49]

Answer:

y=4x/3+9/3

Step-by-step explanation:

slop is 4x/3

and the point is 3,6

so y-6 = 4x/3(x-3)

sove the you will have y=4x/3+9/3

7 0
3 years ago
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