∠ACB is an inscribed angle, so
m∠ACB= (1/2)mAB =(1/2)*50=25⁰
m∠ACB= 25⁰
Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
If there are 272.5 rotations in a mile, and 5280 ft in a mile, then there are 5280 ft in 272.5 rotations. Divide 5280 by 272.5 gives us 19.4 ft/rotation.
That's the circumference of the wheel, and since c = πd, 19.4/π = d, d = 6.2 ft. The diameter of the wheel is how tall it is.
Does this help? Any questions?
Answer:
0.0025551
Step-by-step explanation:
Given that:
Mean (m) = 40000
Standard deviation (s) = 2500
P(x < 33,000) :
USing the relation to obtain the standardized score (Z) :
Z = (x - m) / s
Z = (33000 - 40000) / 2500 = - 2.8
p(Z < -2.8) = 0.0025551 ( Z probability calculator)
Probability of Tyre wagering out before mileage limit is reached = 0.0025551
Answer:
Step-by-step explanation:
Two lines are perpendicular if the first line has a slope of 
and the second line has a slope of 
.
With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:
We now know that 
for the first line, which means that the slope of the second line is 
. With this, we have the following equation for our new line:
where 
is the Y-intercept that we now need to determine with the coordinates given in the problem statement, 
:
Finally, we can create our line:
