I NEED HELP PLEASE!!!! Given a real world problem, can you find the unit rate?

Mathematics

1 answer:

Yuliya22 [10]3 years ago

3 0

Here is an example:

Josh bought 7 apples for $21.

21/7 is 3, so one apple costs $3. This is the unit rate.

21/7 simplifies to 3/1, that’s another way to think about it. Simplify the fraction until the denominator is 1.

Hope this helps! Tell me if you have any questions!

You might be interested in

Brainliest if correct please help

Gemiola [76]

Answer:

Step-by-step explanation: I choose d because if you notice there are only 33 marbles in Bag F and Bag F-number of marbles is equal to 1/3 marbles = 11/33 marbles and Bag G contains only 11 marbles which are how many marbles there are in all bags.

8 0

3 years ago

Read 2 more answers

A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2

alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s