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uysha [10]
3 years ago
15

a tree needs to be stake with four wires, each wire is attached to the trunk 6 feet above the ground, and then anchored to the g

round 8 feet from the base of the tree. How many feet of the wire is needed for 5 trees???
Mathematics
1 answer:
stich3 [128]3 years ago
8 0

Answer:

89

Step-by-step explanation:

You might be interested in
What two number multiple to get -72 and add up to -6
hammer [34]

Answer:

6 and -12

Step-by-step explanation:

6×-12=-72

6+(-12)=-6

×^2 -6x-72=0

(x+6) (x-12)

x^2-6x-72=(x+6) (X-12)

7 0
3 years ago
2,114 x 98 *100 points show work
Vlad [161]
I can show you on a piece of paper
Hope this helps *smiles*

6 0
3 years ago
#2
I am Lyosha [343]

You have the right idea that things need to get multiplied.

What should be done is that the entire fraction needs to get multipled by the lowest common denominator of both denominators.

Let's look at the complex numerator. Its denominators are 5 and x + 6. Nothing is common with these, so both pieces are needed.

The complex denominator has x - 3 as its denominator. With nothing in common between it and the complex numerator, that piece is needed.

So we multiply the entire complex fraction by (5)(x + 6)(x -3).

Numerator: (\frac{1}{5} -\frac{5}{x + 6})(5)(x +6)(x-3) =\frac{1}{5}(5)(x +6)(x-3) -   \frac{5}{x + 6}(5)(x +6)(x-3)

= (x+6)(x-3) - (5)(5)(x-3)

= (x+6)(x-3) - 25(x-3)

= (x-3)(x + 6 - 25) <--- by group factoring the common x - 3

= (x -3)(x - 19)

Denominator:

\frac{25}{x - 3} * (5)(x + 6)(x - 3) = (25)(5)(x + 6) = 125(x + 6)


Now we put the pieces together.


Our fraction simplies to (x - 3) (x - 19) / 125 (x + 6)

5 0
3 years ago
Find an equation of variation in which y varies directly as x and y=420 when x= 100. Then find the value of y when x=11.
sweet [91]
Let's Simplify X to equal 1 by dividing by 100. then we divide 420 by 100 to get 4.2, so y=4.2 when x=1, we then multiply by each by 11.

y = 46.2
x = 11
4 0
3 years ago
How do I do this Q11
SashulF [63]
Look at one of the vertices of the heptagon where two squares meet. The angles within the squares are both of measure 90 degrees, so together they make up 180 degrees.

All the angles at one vertex must clearly add up to 360 degrees. If the angles from the squares contribute a total of 180 degrees, then the two remaining angles (the interior angle of the heptagon and the marked angle) must also be supplementary and add to 180 degrees. This means we can treat the marked angles as exterior angles to the corresponding interior angle.

Finally, we know that for any convex polygon, the exterior angles (the angles that supplement the interior angles of the polygon) all add to 360 degrees (recall the exterior angle sum theorem). This means all the marked angles sum to 360 degrees as well, so the answer is B.
5 0
3 years ago
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