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igomit [66]
3 years ago
13

Help plzzzzzzzzzzzzz

Mathematics
1 answer:
nataly862011 [7]3 years ago
8 0
Please check the attached picture

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Ralph Jordan recently bought a new lawnmower for $228.00. If he had to pay 6% sales tax on the lawnmower, what was the total cos
ipn [44]
228*0.06 to get how much tax you're paying
13.68+228 to add tax to the price
The answer is C.241.68
6 0
3 years ago
Read 2 more answers
NEED HELP WITH THIS QUESTION! Thank you
Kay [80]

Answer:

9 meters

Step-by-step explanation:

Area of a parallelogram is base * height.

A = b * h

65.7 = b * 7.3

b = 9 meters

4 0
3 years ago
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The CEO of the Jen and Benny's ice cream company is concerned about the net weight of ice cream in their 50 ounce ice cream tubs
MissTica

Answer:

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=54.98 represent the sample mean

s=8.43 represent the sample deviation

n=26 sample size  

\mu_o =52 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 52, the system of hypothesis would be:  

Null hypothesis:\mu \leq 52  

Alternative hypothesis:\mu > 52  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

P-value  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

7 0
3 years ago
Read 2 more answers
PLEASE HELP FAST!!!!!
kap26 [50]

Answer:

See below

Step-by-step explanation:

<u>Given functions</u>

  • f(x)=8^x
  • g(x)=8^(x+5) + 1

As we see g(x) = f(x + 5) + 1, which means <u>horizontal translation 5 units left</u> and <u>vertical translation 1 unit up</u>.

Answer options are all incorrect

7 0
2 years ago
Simplify.<br> N4 x N7 over n5
Alinara [238K]

Answer:

n^6.

Step-by-step explanation:

n^4 * \frac{n^7}{n^5}

= n^4 * n^{7 - 5}

= n^4 * n^2

= n^{4 + 2}

= n^6.

Hope this helps!

8 0
3 years ago
Read 2 more answers
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