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3 years ago

Can someone explain on how you get a slope of a graph because i am really confuse on how you do it

Mathematics

1 answer:

zvonat [6]3 years ago

7 0

I got you!!

I will just help you on this one|
So the slope on the graph is equal to -4

(LET ME EXPLAIN TO YOU!!)
Given the following points on the graph you see: (-4,1) or (1,-4)

So let (x1, y1) that is equal to (-4,1)

And (x2 y2) is equal to (1,-4)

This is the Formula you use to find the slope of a graph:
M= y2 - y1
M= X2 - x1

So in this case:
M= -4 - 4 = -8= -4
M= 1 - 1 (-1) = 1+1= 2 = -4

So in that case the slope to this line is -4

I Hope you understand this now...
I tried to be a bit more clear for words so I’m sorry if you still don’t get it but that is the answer to this line graph thing that you have as the picture.....

I wanted to test myself if I knew it because I’m a Middle schooler so yeah

Have a Good Day Byeeeee!!!!

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What is the equation in vertex form of the quadratic function with a vertex at (-1, -4) that goes through (1, 8)?

cestrela7 [59]

Answer:

y = 3(x+1)^2 - 4

Step-by-step explanation:The general form of the equation of a quadratic function whose vertex is (h,k) and whose leading coefficient is a is:

y - k = a(x-h)^2, or

y = a(x-h)^2 - k

Substituting the coefficients of the vertex (-1, -4), we get:

y = a(x + 1)^2 - 4

Substituting the coordinates of the given point, (1,8), we get:

8 = a(1+1)^2 - 4, which simplifies to:

8 = a(2)^2 - 4, or

8 = 4a - 4. Then 4a = 12, and a = 3.

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4 years ago

-2x-y=-9<br> 5x-2y=18<br> substitution

KIM [24]

$-2x-y=-9 \\
5x-2y=18 \\ \\
\hbox{solve the first equation for y:} \\
-2x-y=-9 \ \ \ |+2x \\
-y=-9+2x \ \ \ |\times (-1) \\
y=9-2x \\ \\
\hbox{substitute 9-2x for y in the second equation:} \\
5x-2(9-2x)=18 \\
5x-18+4x=18 \\
9x-18=18 \ \ \ |\div 9 \\
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3 years ago

Read 2 more answers

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

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3 years ago

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Yakvenalex [24]

Answer: a = 23 ft.

Reasoning:

The question asks for the value of the leg a, given the tangent of the opposite angle and the length of the adjacent-leg, b.

The ratio that relates the three parameters is:

tan(A) = opposite-leg / adjacent-leg = a / b = a / 23 ft

Solve for a, wich is the unknown:

a = 23ft * tan(A) = 23ft * 1.0 = 23 ft

Answer: 23 ft.

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3 years ago

Did you ever free club is selling wrapping paper for a fundraiser they order 16 cases if each student in the club takes two thir

omeli [17]

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3 years ago

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