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Black_prince [1.1K]
3 years ago
14

Given the following values, what would the stems be? 4, 25, 56, 78, 105, 112 4 though 11 0 though 11 4 though 12 0 though 7

Mathematics
1 answer:
ss7ja [257]3 years ago
3 0

Answer:

  0 though 11

Step-by-step explanation:

The stems are generally the numbers you get when you drop the units digit. The minimum number in your list is 04, so its stem would be 0. The maximum number in your list is 112, so its stem would be 11. You usually want to have the stems cover the entire range from minimum to maximum, so the stems would be 0 through 11.

___

Here's what the "stem and leaf plot" might look like for these values.

0 | 4

1 |

2 | 5

3 |

4 |

5 | 6

6 |

7 | 8

8 |

9 |

10 | 5

11 | 2

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nexus9112 [7]

Answer:

i think its 1 and 2

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2 years ago
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Can someone please<br> Help me?
Mila [183]

9514 1404 393

Answer:

  see below

Step-by-step explanation:

It is easiest to compare the equations when they are written in the same form.

The first set can be written in slope-intercept form.

  y = 2x +7

  y = 2x +7 . . . . add 2x

These equations are <em>identical</em>, so have infinitely many solutions.

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The second set can be written in standard form.

  y +4x = -5

  y +4x = -10

These equations <em>differ only in their constant</em>, so have no solutions.

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The third set is already written in slope-intercept form. The equations have <em>different slopes</em>, so have exactly one solution.

5 0
3 years ago
A circle has a circumference of 50.2450.2450, point, 24 units.<br> What is the radius of the circle?
beks73 [17]

Answer:

r = 8 units

Step-by-step explanation:

The circumference is calculated using C = 2\pi r. Substitute C = 50.24 units. Solve for the radius.

C = 2 \pi r\\50.24 = 2 \pi r\\25.12 = \pi r\\8 = r

7 0
3 years ago
C is the point (-301, 601)<br> Does C lie on the straight line passing through A and B?
Marat540 [252]

Answer:

There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.

To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.

Step-by-step explanation:

Suppose the equation of the straight line that passes through E and F is this:

y = 7x + 2

We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.

10 = 7(1) + 2 = 7 + 2 = 9

10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.

If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.

8 0
2 years ago
What is the answer to this
mojhsa [17]

Answer:

add then subtract the anwser

5 0
3 years ago
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