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2 years ago

BRAINLIEST to correct answer!!

Mathematics

2 answers:

IrinaVladis [17]2 years ago

6 0

They have the same centre point

Len [333]2 years ago

4 0

They are equally spaced so all the circles share the same center point.

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PLEASE HELP!!!<br> Due in 10 minutes!

erastovalidia [21]

Answer:

41ft²

Step-by-step explanation :

8ft - 2ft = 6ft

6ft - 2ft = 4ft

4ft - 1ft = 3ft

3ft * (8ft + 2ft) / 2 = 15ft²

1ft * (8ft + 2ft) = 10ft²

8ft * 2ft = 16ft²

Total : 16 + 15 + 10 = 41ft²

3 0

2 years ago

Read 2 more answers

Please answer this quickly!

kari74 [83]

54/1,000

just do Length x Width x Height

7 0

3 years ago

How do I solve this out??

GuDViN [60]

<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

$\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]$

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

$\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]$

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0

2 years ago

You randomly choose one of the following numbers shown. Find the probability the event can occur choosing a number greater than

sergey [27]

<h3>Answer: 7/11</h3>

======================================================

Explanation:

The event space is the set of outcomes we want to happen.

The event space is {5, 6, 7, 8, 9, 10, 11} which consists of getting a value greater than 4. There are 7 items in this event space. Let A = 7.

The sample space consists of all possible outcomes. The sample space is {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11} and there are 11 items in the sample space. Let B = 11.

Divide the values of A and B to get the answer we're after

A/B = 7/11

This is the probability of selecting a value greater than 4.

7 0

2 years ago

Solve for x: 3/3x + 1/x+4 = 10/7x

Mekhanik [1.2K]

Given,

3/3x + 1/(x + 4) = 10/7x

1/x + 1/(x+4) = 10/7x

Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x

Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,

{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

(x + 4 + 1x) / (x(x + 4)) = 10/7x

(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled.

∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4

∴x = 3

8 0

3 years ago