Answer:
The answer in the procedure
Step-by-step explanation:
we know that
The rule of the reflection of a point over the y-axis is equal to
A(x,y) ----->A'(-x,y)
That means -----> The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same
so
A(3,-1) ------> A'(-3,-1)
The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)
therefore
To reflect a point over the y-axis
Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis
To find x, divide 13.1 by 150 to get <span>0.08733333333.</span>
Answer: x=-1 y=1
Step-by-step explanation:
solve y in 3+2x-y=0
y=3+2x
sub y=3+2x into -3 -7y=10x
-14x- 24= 10x
solve x in -14x-24=10x
x= -1
sub x= -1 into y =3+2x
y=1
so therefore x= -1 and y=1
For the limit approaching 3 from the right, you want to follow the line to the right of x = 3. From the graph you're describing it sounds like that's y = -3.
The RHS limit is -3 even though f(3) = 7
Answer:
The required solution is (5.75,-0.5). It can be written as 
.
Step-by-step explanation:
The given equations are
.... (1)
.... (2)
Multiply the equation (2) by 2.
.... (3)
Subtract equation (1) from equation (3).
Put this value in equation (1).
Therefore the required solution is (5.75,-0.5). It can be written as .
