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timofeeve [1]
3 years ago
15

State whether the given measurements determine zero, one, or two triangles. A = 58°, a = 25, b = 28

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
6 0
I think the answer is one triangle not for sure though
Rom4ik [11]3 years ago
4 0
Well, we can find c with the equation c^2=a^2+b^2
c^2=25^2+28^2    c^2=625+784   c^2=1409    square root both sides to isolate c. c=√1409   c=37.53664876

A = 58°
Tan B=b/a   Tan B=28/25  Tan B=1.12   B=tan^-1(1.12)  B=48.2397003° or B=48°

All triangles have a total of 180° internal angel measurements. 180°-58°-48°=74°
This works because angle C would be the largest angle anyways.
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The radius of a sphere is 6 units.
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Answer:

choice 2) 4/3πr³

Step-by-step explanation:

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A group of 4 friends likes to bowl together, and each friend keeps track of his all-time highest score in a single game. Their h
andre [41]
I believe C is the answer, hope this helps!
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3 years ago
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A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed
PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}},

where \sigma =population standard deviation.

\overline{x}= sample mean

n= sample size

z* = Two-tailed critical z-value.

Given :  \sigma= 20

n= 42

\overline{x}=759

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

3 0
3 years ago
10. A cylindrical can has a base with a diameter of 6 cm. Its height measures 5 cm. What is the total surface area of the can?
eduard

Answer:

  • Total surface area of cylinderal can is 150.8 cm²

<u>Step-by-step </u><u>explanation</u><u>:</u><u> </u>

Given that a cylinderal can has base with a diameter of 6 cm and its height measures 5 cm.

So,

Radius = Diameter/2 = 6/2 = 3 cm

We know that,

  • TSA of cylinder = 2πr(h + r)

Substituting required values:

➝ TSA = 2 × 22/7 × 3(5 + 3)

➝ TSA = 44/ 7 × 3 × 8

➝ TSA = 1056/7

➝ TSA = 150.8 cm²

Hence,

  • <u>Total </u><u>surface </u><u>area </u><u>of </u><u>cylinderal</u><u> </u><u>can </u><u>is </u><u>1</u><u>5</u><u>0</u><u>.</u><u>8</u><u> </u><u>cm²</u>
6 0
2 years ago
Read 2 more answers
If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?
aksik [14]

ab = 8 & a^{2} + b^{2} = 16 so , ( a+b )^{2} = 32 .

<u>Step-by-step explanation:</u>

Here we have , ab= 8 & a^2+b^2=16 i.e. ab = 8  and a^{2} + b^{2} = 16 .

We need to find value of (a+b)^2 i.e. (a+b)^{2} :

It's and identity and we know that ( a+b )^{2} = a^{2} +b^{2} +2ab

⇒ ( a+b )^{2} = a^{2} +b^{2} +2ab

⇒ ( a+b )^{2} = (a^{2} +b^{2}) +2(ab)

⇒ ( a+b )^{2} = (16) +2(8)

⇒ ( a+b )^{2} = (16) +(16)

⇒ ( a+b )^{2} = 32

∴ ab = 8 & a^{2} + b^{2} = 16 so , ( a+b )^{2} = 32 .

6 0
3 years ago
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