Answer:
choice 2) 4/3πr³
Step-by-step explanation:
Answer: (751.05, 766.95)
Step-by-step explanation:
We know that the confidence interval for population mean is given by :-
,
where
=population standard deviation.
= sample mean
n= sample size
z* = Two-tailed critical z-value.
Given : 
n= 42

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576
Now, the 99% confidence interval around the true population mean viscosity :-
![759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)](https://tex.z-dn.net/?f=759%5Cpm%20%282.5760%29%5Cdfrac%7B20%7D%7B%5Csqrt%7B42%7D%7D%5C%5C%5C%5C%3D759%5Cpm%20%282.5760%29%283.086067%29%5C%5C%5C%5C%3D759%5Cpm7.9497%3D%28759-7.9497%2C%5C%20759%2B7.9497%29%5C%5D%5C%5C%3D%28751.0503%2C%5C%20766.9497%29%5Capprox%28751.05%2C%5C%20766.95%29)
∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)
Answer:
- Total surface area of cylinderal can is 150.8 cm²
<u>Step-by-step </u><u>explanation</u><u>:</u><u> </u>
Given that a cylinderal can has base with a diameter of 6 cm and its height measures 5 cm.
So,
Radius = Diameter/2 = 6/2 = 3 cm
We know that,
- TSA of cylinder = 2πr(h + r)
Substituting required values:
➝ TSA = 2 × 22/7 × 3(5 + 3)
➝ TSA = 44/ 7 × 3 × 8
➝ TSA = 1056/7
➝ TSA = 150.8 cm²
Hence,
- <u>Total </u><u>surface </u><u>area </u><u>of </u><u>cylinderal</u><u> </u><u>can </u><u>is </u><u>1</u><u>5</u><u>0</u><u>.</u><u>8</u><u> </u><u>cm²</u>
&
so ,
.
<u>Step-by-step explanation:</u>
Here we have , ab= 8 & a^2+b^2=16 i.e.
and
.
We need to find value of (a+b)^2 i.e.
:
It's and identity and we know that 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
∴
&
so ,
.