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melisa1 [442]
4 years ago
7

Whar is 4x-2 (x-3)=8

Mathematics
2 answers:
Aneli [31]4 years ago
7 0
The answer is x equal to 1
Scrat [10]4 years ago
3 0

Answer:

x = 1

Step-by-step explanation:

distribute parenthesis on left side and simplify

4x - 2x + 6 = 8

2x + 6 = 8 ( subtract 6 from both sides )

2x = 2 ( divide both sides by 2 )

x = 1

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Which are the partial products for 652 × 4 = 2,608
CaHeK987 [17]

Answer:

652 and 4

Step-by-step explanation:

the product is the total

3 0
3 years ago
(a) An angle measures 27°. What is the measure of its complement?
larisa [96]

Answer:

a) 63°

b) 127°

Step-by-step explanation:

Complements are 90° while supplements are 180°.

So you need to find the complement of 27°. So, 90-27=63

To find the supplement, it is 180-53=127

6 0
3 years ago
Why do you subtract exponents when dividing powers with the same base?
Anastasy [175]
Division<span>. If two </span>powers<span> have the </span>same base<span> then we can </span>divide<span> the </span>powers<span>. When we </span>divide powers<span> we </span>subtract<span> their </span>exponents<span>. A negative </span>exponent<span> is the </span>same<span>as the reciprocal of the positive </span><span>exponent</span>
4 0
4 years ago
If f(x) = 3x² tlo, what is f(-7)?
tia_tia [17]

Answer:

Step-by-step explanation:

Be careful how you handle this.

f(-7) = 3(-7)^2

f(-7) = 3* 49     Notice the minus sign disappears. That's because there are 2 of them.

f(-7) = 147

4 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
4 years ago
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