Answer:
The measure of ∠QML is 90°
The measure of ∠PMN is 117°
Step-by-step explanation:
In circle O:
- MQ is a diameter
- LN is a tangent to circle O at point M
- PM and RQ are secants
- m∠PMO is 27°
- m∠MQR is 42
∵ MQ is a diameter of circle O
∵ LN is a tangent to circle O at point M
- A diameter is perpendicular to a tangent at the point of
contact between them (one of end-point of the diameter)
∴ QM ⊥ LN at point M
∴ m∠QML = m∠QMN = 90°
The measure of ∠QML is 90°
∵ m∠PMN = m∠PMO + m∠QMN
∵ m∠PMO = 27° ⇒ given
∵ m∠QMN = 90° ⇒ proved
∴ m∠PMN = 27 + 90
∴ m∠PMN = 117°
The measure of ∠PMN is 117°
Hello : here is the solution :
<span> log 10 = 1</span>
Answer:
Local minimum at x = 0.
Step-by-step explanation:
Local minimums occur when g'(x) = 0 and g"(x) > 0.
Local maximums occur when g'(x) = 0 and g"(x) < 0.
Set g'(x) equal to 0 and solve:
0 = 2x (x − 1)² (x + 1)²
x = 0, 1, or -1
Evaluate g"(x) at each point:
g"(0) = 2
g"(1) = 0
g"(-1) = 0
There is a local minimum at x = 0.
the answer is is D. i.$1,466.92
ii.$5,518.00
iii.$6,621.60
The error is not there. The error is step 4. -34 becomes positive so it is not -51 it's 17. So the answer is 40/17
