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salantis [7]
2 years ago
7

Jeff wants to buy tickets for a football game for his friends. The stadium is selling tickets for $7 each. The stadium requires

a
person to buy at least 4 tickets, and at most 8 tickets. Let x represent the number of tickets, and y represent the total cost.
What is a reasonable range for the price Jeff would pay for tickets?
Group of answer choices



{11, 18, 25, 32, 39}

{28, 35, 42, 49, 56}

{4, 5, 6, 7, 8}

{28, 42, 56, 70, 84}
Mathematics
1 answer:
aniked [119]2 years ago
7 0

Your answer is D){28, 42, 56, 70, 84}

To answer this question you just have to make sure the amount he pays is a multiple of 7.If you know you times table then this should be easy

Times table of 7:

7,14,21,28,35,42,49,55,63,70,77,84.

Now you just need to find an answer choice who has these numbers.Lets check it out!

A) 11 isn't a multiple of 7

B) 56 isn't a multiple of 7

C) None of these are multiples of 7 except 7 so this is also incorrect

D) This is correct because they are all multiples of 7

Hope this makes sense.

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Here we use the equation

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7 0
3 years ago
Read 2 more answers
The class sizes of elementary school classes in a public school district are normally distributed with an unknown population mea
weqwewe [10]

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Step-by-step explanation:

The confidence interval estimate for the population mean is given by :-

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Given : Sample mean: \overline{x}=20

The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : ME=2.86

Now, the confidence interval estimate for the population mean will be :-

20\pm2.86=(20-2.86,\ 20+2.86)=(17.14,\ 22.86)

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution =  (17.14,\ 22.86)

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