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S_A_V [24]
3 years ago
6

Find the selling price of a book with an original price of $49.95 and a 5% tax rate.please be specific on how the answer is the

answer pls help me
Mathematics
1 answer:
borishaifa [10]3 years ago
3 0

Step-by-step explanation:

$52.45

49.95×.05

then add that result to 49.95= answer

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Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

6 0
3 years ago
Which system of equations does not have a real solution
Aloiza [94]

Answer:

the correct answer is y = x 2 + 3x - 5 and x + y = -10

Step-by-step explanation:

5 0
3 years ago
Pre-Calc, please help! Will give brainliest!
Rus_ich [418]

Answer:

Idk

Step-by-step explanation:

8 0
3 years ago
John has 14 boxes of apples. Each box holds 10 apples. If 8 of the boxes are full, and 6 of the boxes are half full, how many ap
cestrela7 [59]
The 8 full boxes have 80 apples (8x10) and the 6 half boxes have 30 apples (6x5).
So: 80+30=110
7 0
3 years ago
Read 2 more answers
At the city museum, child admission is $6.20 and adult admission is $9.50. On Friday, tickets were sold for a total sales of $10
Nostrana [21]

Answer:

98child tickets were sold that day

Step by step Explanation:

Let the number of children= A of the number of adult

Then

6.20C + 9.50A = 1082.0

From the question it was said that four times as many adult tickets as child tickets were sold which implies that number of adult was FOUR times the children, then we can say

A= 4C

Then substitute into the above equation

6.20C + 9.50A = 1082.0

6.20C + 9.50(4C) = 1082.0

6.20C + 38C= 1082.0

44.2C =1082.0

C= 24.48

But we know that

A= 4C

A=4* 24.48

A= 97.9

Therefore ,98child tickets were sold that day

6 0
3 years ago
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