The chosen topic is not meant for use with this type of problem.
However, if you simplify it, your answer is:
x^2 − 2x − 35
Answer:
The probability of of a randomly chosen student being exactly 21 years old.
= 1.293
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given Population size n = 500</em>
<em>Mean of the Population = 20 years and 6 months</em>
<em> = </em>
<em></em>
<em>Standard deviation of the Population = 2 years</em>
Let 'X' be the range of ages of the students on campus follows a normal distribution
Let x =21


<em>The probability of a randomly chosen student being exactly 21 years old.</em>
<em>P( Z≤21) = 0.5 + A( 0.2) </em>
= 0.5 +0.793
= 1.293
Answer:
Step-by-step explanation:
-9x - 15y = -6
9x + 11y = 14
-4y = 8
y = -2
3x - 10 = 2
3x = 12
x = 4
(4, -2)
Answer:
Probability that component 4 works given that the system is functioning = 0.434 .
Step-by-step explanation:
We are given that a parallel system functions whenever at least one of its components works.
There are parallel system of 5 components and each component works independently with probability 0.4 .
Let <em>A = Probability of component 4 working properly, P(A) = 0.4 .</em>
<em>Also let S = Probability that system is functioning for whole 5 components, P(S)</em>
Now, the conditional probability that component 4 works given that the system is functioning is given by P(A/S) ;
P(A/S) = {Means P(component 4 working and system also working)
divided by P(system is functioning)}
P(A/S) = {In numerator it is P(component 4 working) and in
denominator it is P(system working) = 1 - P(system is not working)}
Since we know that P(system not working) means that none of the components is working in system and it is given with the probability of 0.6 and since there are total of 5 components so P(system working) = 1 -
.
Hence, P(A/S) =
= 0.434.