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Readme [11.4K]
3 years ago
9

What is the distance between point A and point B? A number line ranging from negative 8 to 8 with point A at coordinate negative

6 and point B at coordinate 7 Enter your answer in the box. The distance between points A and B on the number line is units. help please unit # 1 question 10
PLZZZZZ !!!!

Mathematics
2 answers:
salantis [7]3 years ago
5 0

Answer:

11

Step-by-step explanation:

i do k12 and its not 13

Marina CMI [18]3 years ago
4 0

Answer: 13.

Simply Count between Coordinates

Which Adds To 13.

Brainly Please.

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Help please <br> 1 3/5 x 2 1/3=
Crank

Answer:

= 56/ 15  and 3 11/15

Step-by-step explanation:

1 3/5 x 2 1/3

= 8/5 x 7/3

3 0
2 years ago
What is the Y intercept of the line graphed on the grid
Alenkasestr [34]

Answer:

5.5

Step-by-step explanation:

The y-intercept of the line graph shown above is the value of the point where the line cuts the y-axis. The y-intercept of this graph is between 5 and 6. However, we can get an accurate value by calculation. This can be done by generating an equation of the line.

Recall the slope-intercept equation, y = mx + b, where m = slope of the line, b = y-intercept.

To generate the equation of the line, first find slope using the points (-2, 7) and (6, 1):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 7}{6 -(-2)} = \frac{-6}{8} = -\frac{3}{4}.

Substitute m = ¾ and the coordinates (6, 1) into the slope-intercept equation to find the y-intercept (b):

y = mx + b

1 = -\frac{3}{4}(6) + b

1 = -\frac{18}{4} + b

1 = -4.5 + b + 4.5

1 + 4.5 = -4.5 + b + 4.5

5.5 = b

Therefore, b = y-intercept = 5.5.

To generate the equation of the line, plug in the values of m and b, we would have:

y = ¾x + 5.5

The y-intercept of the line of the graph is 5.5.

5 0
3 years ago
Can someone help me please
zubka84 [21]
It’s too small zoom in some I will be glad to assist you
7 0
3 years ago
He statement below describes a situation in which opposite quantities combine to make zero:
kozerog [31]
False I’m pretty sure
3 0
2 years ago
A quantity x has cumulative distribution function p(x) = x − x2/4 for 0 ≤ x ≤ 2 and p(x) = 0 for x &lt; 0 and p(x) = 1 for x &gt
34kurt
F_X(x)=\begin{cases}0&\text{for }x2\end{cases}

Recall that the PDF is given by the derivative of the CDF:

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The mean is given by

\mathbb E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\int_0^2\left(x-\dfrac{x^2}2\right)\,\mathrm dx=\frac23

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3 0
3 years ago
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