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abruzzese [7]
2 years ago
14

Can someone please help me?

Mathematics
1 answer:
I am Lyosha [343]2 years ago
7 0
I used to look at the examples i can’t remember now what it is but look at the examples
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Suppose that nine is a factor of a number which statement has to be true
tensa zangetsu [6.8K]
Since 9 is a factor of an unknown number, that means that that number has to be a multiple of 9. If 9 is the factor of something then that something HAS to be a multiple of 9.
6 0
2 years ago
Which sequences of transformations confirm the congruence of shape II and shape I?
defon
The answer is -1 and 12
3 0
3 years ago
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I need help :(((((((
Effectus [21]

Answer:Allen is correct

Step-by-step explanation: Allen is correct because angle 2 has more information than angle 1 and angle 1 is only 30 degrees.

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2 years ago
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Your friend says that 14.5% is equivilent to 14.5
SCORPION-xisa [38]
14.5% = 0.145 = 145/1000

14.5 = 14500/1000

<span>So 14.5% is a hundredth the size of 14.5, so they are not equal and the friend is incorrect.</span>
4 0
3 years ago
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The systolic blood pressure (BP) of adults in the USA is nearly normally distributed with a mean of 121 and standard deviation o
Wittaler [7]

Answer:

Around 0.73% of adults in the USA have stage 2 high blood pressure

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 121 and standard deviation of 16.

This means that \mu = 121, \sigma = 16

Around what percentage of adults in the USA have stage 2 high blood pressure

The proportion is 1 subtracted by the p-value of Z when X = 160. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{160 - 121}{16}

Z = 2.44

Z = 2.44 has a p-value of 0.9927.

1 - 0.9927 = 0.0073

0.0073*100% = 0.73%

Around 0.73% of adults in the USA have stage 2 high blood pressure

5 0
3 years ago
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