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kkurt [141]
3 years ago
8

How are bryophytes and seedless vascular plants alike?

Biology
1 answer:
Llana [10]3 years ago
7 0

Answer:

both undergo vegetative propagation.

Explanation:

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Which of these gymnosperms are known to be important in maintaining the balance of carbon in an ecosystem?
CaHeK987 [17]

The correct answer is:     [D]:

___________________________________________________

                    →   " redwood tree forests " .

___________________________________________________

 <u>Note</u>:  Let us consider the other answer choices.

___________________________________________________

Choice:  [A]:  "garden flowering plants" ;  is incorrect  — since these are not generally considered to be part of a true or traditional "ecosystem" ; and especially since "garden flowering plants" are, in fact, "flowering plants" —  which means that they are "angiosperms" —  <em><u>Not</u></em>  "<em><u>gymnosperms</u></em><em> </em>".

      →  Rule out:  " Choice:  [A] " .

__________________________________________________

Choice:  [B]:  " ferns and liverworts " ; is incorrect — since <em><u>both</u></em>  ferns — as well as liverworts —<u><em> are Not  </em></u><u>"</u><u><em>gymnosperms </em></u>".  

          Liverworts are "bryophytes" {which lack true vascular tissue] ; and ferns are "pterophytes" ["seedless vascular plants"].

      →  Rule out:  " Choice:  [B] " .

___________________________________________________

Choice:  [C]: " mosses and horsetails "; is incorrect ;  since <em><u>both</u></em> mosses — as well as horsetails — <u><em>are Not  </em></u><u>"</u><u><em>gymnosperms </em></u>".   Mosses are "bryophytes" (see aforementioned) ; and horsetails are "non-seed bearing plants" that spread vegetatively [underground; by asexual reproduction — <em><u>and Not by seed</u></em><em> .</em>].

      →  Rule out:  " Choice:  [C] " .

__________________________________________________

Choice:  [D]: " redwood tree forests "  ;

               — is the only answer choice provided that is a "gymnosperm".    

             Furthermore, the "redwood tree" is a conifer (i.e. "coniferous; or, "cone-bearing" plant} that reproduces through seeds spread by "cone") — and all "conifers" are a type of "gymnosperm."  

            Furthermore, "redwood trees" grow large and tall, and redwood forest communities within an ecosystem; due to there size and presence, are:  "<em><u>known to be important in maintaining the balance of carbon in an ecosystem</u></em>."

__________________________________________________

 →  As such, the correct answer is:

__________________________________________________

 →  Answer choice:  [D]:  " redwood tree forests " .

__________________________________________________

Hope this helps!

    Best wishes to you in your academic endeavors

           — and within the "Brainly" community!

__________________________________________________

5 0
3 years ago
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Which of the following is not a component of the endomembrane system?
Naya [18.7K]

Answer:

Mitochondria

Explanation:

In the eukaryotic cells, some cell organelles and membranes together make a membrane system called the endomembrane system. This system includes the endoplasmic reticulum, Golgi apparatus, lysosomes and nuclear membrane.  Members of this system works together. They modify, package, and transport lipids and proteins. The lysosomes formed from Golgi apparatus and contains hydrolytic enzymes. Mitochondria is the site for cellualr respiration and is not a part of the endomembrane system.  

4 0
3 years ago
A population of mollusks has lived in a relatively stable environment and shown no great change in many, many years. They live,
g100num [7]
Answer choice A. Stasis.
Stasis is a block of little to no change in a species.
7 0
3 years ago
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A DNA fragment with the sticky end sequence TGGCA will bind with another DNA fragment with the sticky end sequence _____
klio [65]

Answer:

A DNA fragment with sticky end sequence TGGCA will bind with another DNA fragment with sticky end sequence ACCGT.

Explanation:

When a DNA strand is separated by the restriction endonuclease, it forms two separate single strands. These strands or cuts are known as sticky ends as they are detached from the complementary pairs.

These cuts of DNA are without complementary pairs and when they find suitable base pair, they get attached to it. These sticky ends are allowed to fix with the complementary base pairs during PCR/ polymerase chain reaction.

They are called sticky ends as they are ready to stick with the complementary base pairs of nucleotides.

6 0
3 years ago
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What can you learn from observing and comparing specific physical traits of different birds
Natali5045456 [20]
When you observe and compare specific physical traits of different birds you will learn that some birds have characteristics that help them live and survive in their own habitat that other birds may not have but make up those birds have characteristics that help them in their own habitat.  
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3 years ago
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