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2 years ago

If the reactants of wood when burning weigh 10 kgs, how much will the products weigh?

Chemistry

1 answer:

aksik [14]2 years ago

7 0

Answer:

the weight of products is is equal the weight of the wood plus the weight of oxygen that was used to burn that wood, so weigh of the product is greater than 10 kilograms.

Explanation:

Conservation of mass (mass is never lost or gained in chemical reactions), during chemical reaction no particles are created or destroyed, the atoms are rearranged from the reactants to the products.

In this example wood (mostly carbon) and oxygen are reactants and carbon dioxide (mostly) is product of reaction.

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A quantity of liquid methanol, CH3OH, is introduced intoa rigid 3.00-L vessel, the vessel is sealed, and the temperature israise

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Answer:

74,3 grams is the mass of methanol that was initially introduced into the vessel

Explanation:

CH3OH(g) ----> 1 CO(g) + 2 H2(g)

initial: Idk what i have (X) - -

react: initial - react react react

equilibrium: A concentration A conc. 0.426 M

in equilibrum in eq

See that in equilibrium are formed 2 moles of H2 with this concentration, 0,426M and you form 1 mol of CO, so the moles that are formed of H2 are the double of CO, because stoychiometry.

CH3OH(g) ----> 1 CO(g) + 2 H2(g)

initial: Idk what i have (X) - -

react: initial - react react react

equilibrium: A conc. in eq 0,213 M 0.426 M

So we have concentrations of products in equilibrium, and we have Kc, now we can find concentration of reactants in equilibrium

Kc = ([CO] . [H2]*2) / [CH3OH]

6,9X10*-2 = (0,213 . 0,426*2) / [CH3OH]

[CH3OH] = (0,213 . 0,426*2) / 6,9X10*-2

[CH3OH] = 0,560 M

You know that 1 mol which reacted has this concentration in equilibrium, 0,213 M so I can know what's my initial concentration of reactive

Initial - react = equilibrium

initial - 0,213M = 0,560M ---> Initial = 0,773 M

0,773M is initial concentration of CH3OH, but this is molarity, (moles in 1L). My volume is 3 L so

1 L _____ 0,773 moles

3 L _____ 3L . 0,773moles = 2,319 (the moles that i used)

Molar mass CH3OH = 32.06 g/m

Moles . molar mass = grams ---> 2,319 moles . 32,06 g/m = 74,3 g

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