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3 years ago

12

Is the following is a correct statement of Charless Law? The volume of a gas varies directly with the absolute temperature under

the conditions of constant pressure.

1 answer:

guapka [62]3 years ago

4 0

<span>Yes, that is reasonable. Volume and absolute temperature are linearly related, assuming constant pressure</span>

You might be interested in

Calculate the amount of CO2 (in kg) released when 1 kg of coal is burned. Assume that carbon content of the coal is 50% by mass.

Delvig [45]

Answer:

1.8321 kg

Explanation:

The given 1 kg of coal contains 50% of the carbon atom by mass. Thus, mass of carbon in coal is $\frac {50}{100}\times 1\ kg=0.5\ kg$

Also, 1 kg = 1000 g

So, mass of carbon = 500 g

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Molar mass of carbon = 12.0107 g/mol

Moles of methanol = 500 g / 12.0107 g/mol = 41.6295 moles

Considering the reaction:

$C+O_2\rightarrow CO_2$

From the reaction,

1 mole of C react to form 1 mole of $CO_2$

So,

41.6295 moles of C react to form 41.6295 moles of $CO_2$

Moles of $CO_2$ = 41.6295 moles

Molar mass of $CO_2$ = 44.01 g/mol

So, Mass = Moles × Molar mass = 41.6295 moles × 44.01 g/mol = 1832.1143 g

Also, 1g = 0.001 kg

<u>So, amount of $CO_2$ released = 1.8321 kg</u>

4 0

3 years ago

Calculate the mass of dry ice that should be added to the water so that the dry ice completely sublimes away when the water reac

riadik2000 [5.3K]

There are a lot of missing information in this problem. I've found a similar problem which is shown in the attached picture. Let's just use the information there that we don't have here.

From the principle of conservation of energy:

Heat of dry ice + Heat of water = 0
Heat of dry ice = - Heat of water
(m of dry ice)ΔH = -(m of water)(Cp)(ΔT)
where Cp for water is 4.187 kJ/kg·°C

Hence,
(m of dry ice)(ΔH°g - ΔH°s) = -(Density*Volume)(Cp)(ΔT)
where the density of water is 1 kg/L and the molar mass of dry ice is 44 g/mol.

Then,
(m of dry ice)(-393.5 - -427.4 kJ/mol)(44 g/mol) = -(1 kg/L*12L)(4.187 kJ/kg·°C)(16 - 88 °C)
Solving for m of dry ice,
<em>Mass = 2.43 g of dry ice</em>

8 0

3 years ago

Why does neon gas consist of individual, unbonded neon atoms while chlorine exists as diatomic chlorine molecules?

nlexa [21]

Neon gas consist of individual, unbonded neon atoms due to the stable (octet) configuration, while chlorine exists as diatomic chlorine molecules to gain stability.

<h3>How we define the stability of atoms?</h3>

Stability of any atom will be defined on the basis of the electronic configuration or the number of valence shell electrons they have.

Chlorine atom have seven electrons on the outermost shell of the atom and will able to gain 1 electron to get octet configuration, that's why present in the diatomic form.
Neon is a noble gas as they have stable configuration due to presence of 8 electrons in the valence shell, and due to stability it will not easily react with any other gas and present in single atomic form.

Hence due to stable configuration of neon it is present in the unbonded form.

To know more about octet configuration, visit the below link:

brainly.com/question/15076797

#SPJ1

6 0

2 years ago

A gas has a volume of 4.25 m3 at a temperature of 95.0°C and a pressure of 1.05 atm. What temperature will the gas have at a pre

Goryan [66]

Answer:

$\boxed {\boxed {\sf 82.7 \textdegree C}}$

Explanation:

We are asked to find the temperature of a gas given a change in pressure and volume. We will use the Combined Gas Law, which combines 3 gas laws: Boyle's, Charles's, and Gay-Lussac's.

$\frac {P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Initially, the gas has a pressure of 1.05 atmospheres, a volume of 4.25 cubic meters, and a temperature of 95.0 degrees Celsius.

$\frac {1.05 \ atm * 4.25 \ m^3}{95.0 \textdegree C}= \frac{P_2V_2}{T_2}$

Then, the pressure increases to 1.58 atmospheres and the volume decreases to 2.46 cubic meters.

$\frac {1.05 \ atm * 4.25 \ m^3}{95.0 \textdegree C}= \frac{1.58 \ atm *2.46 \ m^3}{T_2}$

We are solving for the new temperature, so we must isolate the variable T₂. Cross multiply. Multiply the first numerator by the second denominator, then multiply the first denominator by the second numerator.

$(1.05 \ atm * 4.25 \ m^3) * T_2 = (95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)$

Now the variable is being multiplied by (1.05 atm * 4.25 m³). The inverse operation of multiplication is division, so we divide both sides by this value.

$\frac {(1.05 \ atm * 4.25 \ m^3) * T_2}{(1.05 \ atm * 4.25 \ m^3)} = \frac{(95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)}{(1.05 \ atm * 4.25 \ m^3)}$

$T_2=\frac{(95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)}{(1.05 \ atm * 4.25 \ m^3)}$

The units of atmospheres and cubic meters cancel.

$T_2=\frac{(95.0 \textdegree C)*(1.58* 2.46 )}{(1.05 * 4.25 )}$

Solve inside the parentheses.

$T_2= \frac{(95.0 \textdegree C)*3.8868}{4.4625}$

$T_2= \frac{369.246}{4.4625} \textdegree C}$

$T_2 = 82.74420168 \textdegree C$

The original values of volume, temperature, and pressure all have 3 significant figures, so our answer must have the same. For the number we calculated, that is the tenths place. The 4 in the hundredth place to the right tells us to leave the 7 in the tenths place.

$T_2 \approx 82.7 \textdegree C$

The temperature is approximately <u>82.7 degrees Celsius.</u>

3 0

3 years ago

Which of an atom's electrons are involved in chemical reactions?

Nadya [2.5K]

it’s C

i hope i help you but if not DO NOT FORGET STAY SAFE AT HOME

4 0

3 years ago