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Pavel [41]
3 years ago
13

A gas sample at 40.0*C occupies a volume of 2.32 L. If the temperature is raised to 75*C, what will the volume be, assuming the

pressure remains constant?
Chemistry
1 answer:
sammy [17]3 years ago
8 0

Answer: 2.58L

Explanation:

We must convert the temperature from °C to Kelvin temperature

T1 = 40°C = 40 + 273 = 313K

V1 = 2.32 L

T2 = 75°C = 75 + 273 = 348K

V2 = ?

V1 /T1 = V2 /T2

2.32 / 313 = V2 / 348

Cross multiply to express in linear form

313 x V2 = 2.32 x 348

Divide both side by the coefficient of V2 ie 313. We have

V2 = (2.32 x 348) /313

V2 = 2.58L

Therefore, if the temperature is raised to 75°C, the volume of the gas will be 2.58L

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Stuck stupid science homework. anyone know answers?
Veronika [31]
The charge of a Rb ion would be +1
7 0
2 years ago
Aspirin can be prepared from salicylic acid ( C 7 H 6 O 3 CX7HX6OX3), which has a molar mass of 138.12 g/mol, and acetic anhydri
pychu [463]

Answer: The theoretical yield of aspirin is 4.14 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of salicylic acid}=\frac{3.20g}{138.12g/mol}=0.023moles

mass of acetic anhydride = density\times volume =1.082g/ml\times 3.71ml=4.01g

\text{Moles of acetic anhydride}=\frac{4.01g}{102.04g/mol}=0.039moles

C_9H_6O_3+C_4H_6O_3\rightarrow C_9H_8O_4+C_2H_3O_2  

According to stoichiometry :

1 mole of salycylic acid require 1 mole of acetic anhydride

Thus 0.023 moles of  salycylic acid require=\frac{1}{1}\times 0.023=0.023moles  of acetic anhydride

Thus salycylic acid is the limiting reagent as it limits the formation of product and acetic anhydride is the excess reagent.

As 1 mole of salycylic give = 1 mole of aspirin

Thus 0.023 moles of salycylic acid give =\frac{1}{1}\times 0.023=0.023moles  of aspirin

Mass of aspirin = moles\times {\text {Molar mass}}=0.023moles\times 180.15g/mol=4.14g

Thus theoretical yield of aspirin is 4.14 g

4 0
3 years ago
20 poll
aleksley [76]

Answer: n=15.56moles

Explanation:

PV = nRT

where  

P is pressure in atmospheres

V is volume in Liters

n is the number of moles of the gas

R is the ideal gas constant = given as (0.0821L -atm/k-mol

PV = nRT

n= PV/RT

n= (1.5 X 230)/ (0.0821  X 270)

n= 15.56 moles

5 0
3 years ago
A sample of water is heated from 60.0 °C to 75.0°C by the addition of 140 j of
kupik [55]

Mass of the water : 2.23 g

<h3>Furter explanation</h3>

Heat

Q = m.c.Δt

m= mass, g

c = heat capacity, for water : 4.18 J/g° C.

ΔT = temperature

Q= 140 J

Δt = 75 - 60 = 15

mass of the water :

\tt m=\dfrac{Q}{c.\Delta T}=\dfrac{140}{4.18\times 15}=2.23~g

5 0
2 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

6 0
2 years ago
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