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zmey [24]
3 years ago
6

Andrew and Kate have $30 to spend on dinner, tax, and gratuity at Mo’s Restaurant. Tax is 6%, and they will give a 15% tip on th

e total bill after taxes. Their dinner costs $21.00. Which statement correctly explains whether Andrew and Kate have enough money to pay their bill?
Yes. They have enough to pay their bill: 30 dollars times 1.06 = 31 dollars and 80 cents and 31 dollars and 80 cents times 1.15 = 36 dollars and 57 cents.
Yes. They have enough to pay their bill: 21 dollars times 1.06 = 22 dollars and 26 cents and 22 dollars and 26 cents times 1.15 = 25 dollars and 60 cents.
No. They do not have enough to pay their bill: 30 dollars times 1.06 = 31 dollars and 80 cents and 31 dollars and 80 cents times 1.15 = 36 dollars and 57 cents.
No. They do not have enough to pay their bill: 21 dollars times 1.06 = 22 dollars and 26 cents and 22 dollars and 26 cents times 1.15 = 25 dollars and 60 cents.


BRAINLYIST PROVIDED
Mathematics
2 answers:
valina [46]3 years ago
8 0
The second question is correct
Anton [14]3 years ago
4 0

Answer:

yes, the meal costs 25.60

Step-by-step explanation:

I used a slightly different method but B (Yes. They have enough to pay their bill: 21 dollars times 1.06 = 22 dollars and 26 cents and 22 dollars and 26 cents times 1.15 = 25 dollars and 60 cents.) is correct.

21*0.06=1.26

1.26+21=22.26

22.26*0.15=3.34

22.26+3.34=25.60

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Answer:

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Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

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                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

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\mathbf{c)}

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                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

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\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

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