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2 years ago

15

If the unit selling price is $2.50 and the unit cost is $1.00, what action is needed to maintain the gross margin percentage whe

n unit cost increases $0.25?*

1 answer:

erica [24]2 years ago

3 0

The answer is $3.75 b/c you add all of them together and you get $3.75 hope that it help you?

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In 5 minutes, Joey eats 25 hot dogs. how many hot dogs did he eat in a minute?

Colt1911 [192]

Answer: He Had 5 Per Min.

25 ÷ 5 = 5

5 Per Min.

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2 years ago

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The diameter (d) of a circle with a circumference of 440 cm is: Use Π = 22/7

elena-s [515]

Answer:

c

Step-by-step explanation:

c=2*22/7r

440=44/7r

440*7/44=r

70=r

d=2r

d=2*70

d=140 cm

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1 year ago

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Time between 22:30 and 04:20

Svetlanka [38]

The answer would be 5 hours and 50 minuets. It would be this because 2230 equals 10:30 count the hours between 1030 and 430 6 hrs then minus 10 min because the last hr isnt a full hour because it doesnt make it to 430.

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2 years ago

Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1

Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

$x'=\frac{dx}{dt}$

a) x’=t–sin(t), x(0)=1

$dx=(t-sint)dt$

Apply integral both sides:

$\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k$

where k is a constant due to integration. With x(0)=1, substitute:

$1=0+cos0+k\\\\1=1+k\\k=0$

Finally:

$x=\frac{t^2}{2} +cos(t)$

b) x’+2x=4; x(0)=5

$dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\$

Completing the integral:

$-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}$

Solving the operator:

$-\frac{1}{2}ln(4-2x)=t+k$

Using algebra, it becomes explicit:

$x=2+ke^{-2t}$

With x(0)=5, substitute:

$5=2+ke^{-2(0)}=2+k(1)\\\\k=3$

Finally:

$x=2+3e^{-2t}$

c) x’’+4x=0; x(0)=0; x’(0)=1

Let $x=e^{mt}$ be the solution for the equation, then:

$x'=me^{mt}\\x''=m^{2}e^{mt}$

Substituting these equations in <em>c)</em>

$m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i$

This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>

$x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)$

Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:

$x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}$

Finally:

$x=\frac{1}{2} sin(2t)$

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3 years ago

How do you solve ∛216 and explain

Gennadij [26K]

The answer is 6 as 6 x 6 x 6 = 216

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3 years ago