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liq [111]
3 years ago
10

Martha is making 5 batches of cookies. Each batch uses 3/4 cup butter. How much butter does she need for all of her cookies?

Mathematics
1 answer:
inysia [295]3 years ago
4 0

Answer:

3 1/2 cups butter

Step-by-step explanation:

Multiply the batches (5) by the amount of butter (3/4 cup)

5/1 * 3/4 = 5*3 = 15; 1*4 =4     15/4

Divide 15 by 4 to turn from improper fraction to mixed number:

15/4 = 3 and 2/4; reduce to 3 1/2

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Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
2 years ago
Question Help
Oxana [17]
X + y = 23000

x.08 + y.09 = 2040

x = 23000 - y

(23000 - y) .08 + y.09 = 2040

1840 - .08y + .09y = 2040

Simplify

.01y = 200

Simplify

Y = 20000

X + 20000 = 23000

X = 3000

CHECK: .08x + .09(20000) = 2040

.08x + 1800 = 2040

Simply .08x = 240

X = 3000
7 0
3 years ago
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