Answer:
The given statement is true because the person they did their steps correctly
a) Locate a point C so that ABC is a right triangle with m ACB ∠ = ° 90 and the measure of one of the acute angles in the triangle is 45° .
b) Locate a point D so that ABD is a right triangle with m ADB ∠ = ° 90 and
the measure of one of the acute angles in the triangle is30° .
c) Locate a point E so that ABE is a right triangle with m AEB ∠ = ° 90 and
the measure of one of the acute angles in the triangle is15° .
d) Find the distance between point C and the midpoint of segment AB .
Repeat with points D and E.
e) Suppose F is a point on the graph so that ABF is a right triangle
withm AFB ∠ =° 90 . Make a conjecture about the point F.
Answer:
B) 15.85%
Step-by-step explanation:
normalcdf(minimum,maximum,μ,σ)
normalcdf(39,189,264,75)
≈0.1573
≈15.73%
Therefore, the closest answer is B
Answer:
1. the range of f^-1(x) is {10, 20, 30}.
2. the graph of f^-1(x) will include the point (0, 3)
3. n = 8
Step-by-step explanation:
1. The domain of a function is the range of its inverse, and vice versa. The range of f^-1(x) is {10, 20, 30}.
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2. See above. The domain and range are swapped between a function and its inverse. That means function point (3, 0) will correspond to inverse function point (0, 3).
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3. The n-th term of an arithmetic sequence is given by ...
an = a1 +d(n -1)
You are given a1 = 2, a12 = 211, so ...
211 = 2 + d(12 -1)
209/11 = d = 19 . . . . . solve the above equation for the common difference
Now, we can use the same equation to find n for an = 135.
135 = 2 + 19(n -1)
133/19 = n -1 . . . . . . . subtract 2, divide by 19
7 +1 = n = 8 . . . . . . . . add 1
135 is the 8th term of the sequence.
Answer:
32+d
Step-by-step explanation:
because it's asking for 32 added on to whatever d is
example
if d=5 it would be asking what's 32 +5
Answer:
120°
Step-by-step explanation:
All the angles of an equilateral triangle are equal, and hence have a measure of 60°.
∵ ∠AGF is a part of equilateral Δ AGF, m∠AGF = 60°.
∵ ∠FGE is a part of equilateral Δ AGF, m∠FGE = 60°.
Also note that ∠AGE = ∠AGF + ∠FGE.
⇒ m∠AGE = m∠AGF + m∠FGE
⇒ m∠AGE = 60° + 60°
= 120°.
