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3 years ago

How do i add someone to an existing slack conversation?

Computers and Technology

1 answer:

IrinaVladis [17]3 years ago

7 0

To add a new member to an existing conversation in slack app you have to follow 5 steps

Slack is a computer program and application that has the following functions:

Communication and online work
File upload
Video conferencing (paid version)

This tool is available on the following operating systems:

Android
iOs
Mac
Windows
Linux

To add a new person to an existing conversation we follow the following steps:

Open the conversation to which we want to add another person
We click on the right part where it says Members
We click on the button that says Add people
We write the name of the person we want to add or we click on their name
We click on Go

Learn more in: brainly.com/question/2919814

Learn more in:

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What is output?

Misha Larkins [42]

Answer:

The output of code will be 10

Explanation:

We need to find output of following code:

C = 1

Sum = 0

while (c less than 10):

C = c + 3

sum = sum + c

print (sum)

Solution:

We will check the condition of while loop, if the condition is true, then the statements inside the loop will be executed. Since brackets are not available so, only one statement is linked with while loop.

First while loop will be executed c < 10 (1<10) the condition becomes true, and statement c=c+3 will be executed ( 4=1+3) and then loop condition will be checked (4<10) the condition becomes true, and statement c=c+3 will be executed ( 7=4+3) and then loop condition will be checked (7<10) the condition becomes true and statement c=c+3 will be executed ( 10=7+3) and then loop condition will be checked (10<10) the condition becomes false, so we will come outside loop body and execute: sum=sum+c (10=0+10) and print sum i. e 10

So, The output of code will be 10

6 0

3 years ago

What's the value of this Python expression? ((10 >= 5*2) and (10 <= 5*2))

elena-14-01-66 [18.8K]

Answer:

The Boolean value returned by that expression will be True

Explanation:

We have two logical statements in that expression:

Expression 1: (10 >= 5*2)

This can be read as: is 10 greater than or equal to 5 multipled by 2. This evaluates to true as 10 is equal to 5 * 2. Hence expression 1 returns true

Expression 2: (10 <= 5*2)

This can be read as: is 10 less than or equal to 5 multiplied by 2. This also evaluates to true as 10 is equal to 5*2. Hence expression 2 returns true.

Now between this two expression is the and operator which evaluates to true if and only if both logical expressions returnes true.

True and True ==> True

Since Expression 1 ==> True and Expression 2 ==> True

This means Expression 1 and Expression 2 ==> True which is the Boolean value returned by the statement

5 0

3 years ago

In most presentation software, custom animations are added from the _____.

gtnhenbr [62]

Answer:

Explanation:

the answer is.....normal view

8 0

3 years ago

An online museum is creating a site hosting hundreds of thousands of digital representations of art from around the world. The w

Firdavs [7]

Answer:

A. the museum can choose a heuristic approach which will achieve a lossless compression, but they cannot be sure that it is the most efficient compression for each image

C. algorithms for lossless compression exist, so the museum can use those to compress the image

Explanation:

4 0

3 years ago

(JAVA PLS)

Elza [17]

import java.util.Scanner;

public class JavaApplication54 {

public static int appearance(String word, char letter){

int count = 0;

for (int i = 0; i < word.length(); i++){

if (word.charAt(i) == letter){

count++;

}

return count;

}

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

System.out.println("Type the message to be shortened");

String message = scan.nextLine();

message = message.toLowerCase();

int volCount = 0, repCount = 0, num = 0;

char prevC = ' ';

String vowels = "aeiou";

String newMessage = "";

for (int i = 0; i < message.length(); i++){

char c = message.charAt(i);

if (vowels.indexOf(c) != -1 && prevC == ' '){

newMessage += c;

}

else if (vowels.indexOf(c) == -1 && prevC != c){

newMessage += c;

}

else if (vowels.indexOf(c) != -1){

volCount ++;

}

else{

repCount++;

}

prevC = c;

}

System.out.println("Algorithm 1");

System.out.println("Vowels removed: "+volCount);

System.out.println("Repeats removed: "+repCount);

System.out.println("Algorithm 1 message: "+newMessage);

System.out.println("Algorithm 1 characters saved: "+(message.length() - newMessage.length()));

String uniqueMessage = "";

for (int i = 0; i<message.length(); i++){

char w = message.charAt(i);

if (uniqueMessage.indexOf(w)== -1 && w!=' '){

uniqueMessage += appearance(message,w)+""+w;

num++;

}

System.out.println("Algorithm 2");

System.out.println("Unique characters found: "+num);

System.out.println("Algorithm 2 message: "+uniqueMessage);

System.out.println("Algorithm 2 characters saved: "+(message.length() - uniqueMessage.length()));

}

I hope this helps!

6 0

3 years ago