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inn [45]
3 years ago
13

Create the logic for a program that calculates and displays the amount of money you would have if you invested $5000 at 2 percen

t interest for one year. Create a separate method to do the calculation and return the result to be displayed.

Computers and Technology
2 answers:
avanturin [10]3 years ago
8 0

Answer:

# main function is defined

# the calculateAmount is called here

def main():

   print("The new amount is: ", calculateAmount(), sep="")

   

# calculateAmount function that calculate the interest

def calculateAmount():

   # the value of principal is p

   p = 5000

   # the value of rate is r

   r= 2

   # the time is t

   t = 1

   # the formula for finding interest

   interest = (p * r * t) / 100

   # the new amount is calculated

   amount = p + interest

   # the amount is returned

   return amount

# a call that make main function begin execution

if __name__ == "__main__":

   main()

Explanation:

The program is written in Python and it is well commented. A screenshot is attached showing program output

Wewaii [24]3 years ago
4 0

Answer:

public class num7 {

   /* Interest = (Principal *Rate*Time)/100

       Total amount you will have = principal (5000)+Interest

    */

   public static void main(String[] args) {

       double prinAmount = 5000;

       System.out.println("The total amount is "+(calInterest(prinAmount)));

   }

   static double calInterest(double principal){

       int time =1;

       double rate = 2.0;

       double interest = (principal*rate*time)/100;

       double principalPlusInterest = principal+interest;

       return principalPlusInterest;

   }

}

Explanation:

The Logic for this program is:

Interest = (Principal *Rate*Time)/100

Total amount you will have = principal (5000)+Interest

The method calInterest()  accepts a double parameter (principal Amount) and uses the logic above to calculate and return the total amount.

The Main Method calls calInterest() and outputs the value calculated in this case since it is hardcoded 5100

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Answer:

Check the explanation

Explanation:

#!usr/bin/python

#FileName: sieve_once_again.py

#Python Version: 2.6.2

#Author: Rahul Raj

#Sat May 15 11:41:21 2010 IST

 

fi=0 #flag index for scaling with big numbers..

n=input('Prime Number(>2) Upto:')

s=range(3,n,2)

def next_non_zero():

"To find the first non zero element of the list s"

global fi,s

while True:

if s[fi]:return s[fi]

fi+=1

def sieve():

primelist=[2]

limit=(s[-1]-3)/2

largest=s[-1]

while True:

m=next_non_zero()

fi=s.index(m)

if m**2>largest:

primelist+=[prime for prime in s if prime] #appending rest of the non zero numbers

break

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primelist.append(m)

while ind<=limit:

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ind+=m

s[s.index(m)]=0

#print primelist

print 'Number of Primes upto %d: %d'%(n,len(primelist))

if __name__=='__main__':

sieve()

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Answer:import functools

# open your file

file = open("integers.txt", 'r')

file = file.read()

# put numbers into a list

file = file.split()

# convert list into integers

file = list(map(int, file))

# use lambda function to get average.

print(functools.reduce(lambda x, y: x+y / len(file), file, 0))

Explanation:

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