What is the solution of d²–12 = 0?
1 answer:
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First lets look at our graph of y = cos x
***First picture***
Next lets look at a <span>vertical stretch.
***Second picture***
To vertically stretch y = cos x, we need to multiply cos by a number greater than 1. I am going to use 2.
Standard Form: y = cos x (Red Line)
Vertical Stretch: y = 2 cos x (Blue Line)
Lets look at a vertical shrink
***Third picture***
To create a vertical shrink, you multiply the cos by a number less than 1. I am going to use .5
</span>Standard Form: y = cos x (Red Line)
Vertical Shrink: y = .5 cos x (Green Line)
Now lets look at horizontal stretch.
***Forth picture.***
To create a horizontal stretch, you multiply the x by a value less than 1. I am going to use .5
Standard Form: y = cos x (Red Line)
Vertical Stretch: y = .5 cos x (Orange Line)
Finally, to create a horizontal shrink, you multiply the x by a value greater than 1. I am going to use 2.
***Fifth picture.***
Standard Form: y = cos x (Red Line)
Vertical Shrink: y = 2 cos x (Purple Line)
***First picture***
Next lets look at a <span>vertical stretch.
***Second picture***
To vertically stretch y = cos x, we need to multiply cos by a number greater than 1. I am going to use 2.
Standard Form: y = cos x (Red Line)
Vertical Stretch: y = 2 cos x (Blue Line)
Lets look at a vertical shrink
***Third picture***
To create a vertical shrink, you multiply the cos by a number less than 1. I am going to use .5
</span>Standard Form: y = cos x (Red Line)
Vertical Shrink: y = .5 cos x (Green Line)
Now lets look at horizontal stretch.
***Forth picture.***
To create a horizontal stretch, you multiply the x by a value less than 1. I am going to use .5
Standard Form: y = cos x (Red Line)
Vertical Stretch: y = .5 cos x (Orange Line)
Finally, to create a horizontal shrink, you multiply the x by a value greater than 1. I am going to use 2.
***Fifth picture.***
Standard Form: y = cos x (Red Line)
Vertical Shrink: y = 2 cos x (Purple Line)