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2 years ago

How many ways can 6 people line up at the door ?

Mathematics

2 answers:

Svetlanka [38]2 years ago

4 0

It seems that this isn’t the full question. Please list the full questio, so me and others can answer it for you.

bekas [8.4K]2 years ago

4 0

Answer:

I'd say they could in 4 ways.

Step-by-step explanation:

In a vertical line, a horizontal line, diagonal one way, then diagonal the other way.

You might be interested in

If (-1,4) and (3,-2) are end points of diameter of the circle, then the equation of the circle is

Volgvan

Answer:

If you've more doubts you can ask :)

Step-by-step explanation:

If the centre of a circle is (a, b) and radius r, then the equation of the circle is :

$(x - x)^2 + (y-b)^2 = r^2$

First we will find the centre, (a , b):

$a = \frac{3+(-1)}{2} = \frac{2}{2} = 1\\\\b = \frac{-2 + 4}{2} = \frac{2}{2} = 1$

Find radius:

$Radius, r = \frac{Diameter}{2}$

Diameter is the distance between (-1, 4) and (3, -2)

$diameter = \sqrt{(x_2 - x_1)^2 +(y_2-y_1)^2} \\\\$

$= \sqrt{(3-(-1)^2 + (-2-4)^2} \\\\=\sqrt{16 + 36}\\\\=\sqrt{52}\\\\=\sqrt{4 \times 13}\\\\=2\sqrt{13} \ units$

Therefore , $r = \frac{2 \times \sqrt{13} }{2} = \sqrt{13} \ units$

Equation of the circle is :

$(x - 1)^2 +(y-1)^2 = 13$

4 0

2 years ago

A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d

Alenkasestr [34]

Answer:

μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

Distance 1:

- Ff*d₁ = Ef - Ei

⇒ - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ

⇒ - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ (I)

Distance 2:

- Ff*d₂ = Ef - Ei

⇒ - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒ μ*g*d₂ = 0.5*v² (II)

If we apply (I) + (II)

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ (III)

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁ ⇒ vf² = 2*g*Sin θ*d₁ = v²

then (from the equation III) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒ μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒ μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK ⇒ - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁ ⇒ d₂ = Sin θ*d₁ / μ

3 0

3 years ago

Surface area of solid cuboid 8cm 6cm 2cm

strojnjashka [21]

Answer:

152 $\text{cm}^2$

Step-by-step explanation:

We know that the total surface area of a cuboid is the sum of the surface area of all six of its faces.

We also know that each opposing side has the same surface area. Thus the total surface area is equal to:

$2*(8*6+8*2+6*2)\\\\=2*(48+16+12)\\=2*76\\=152$ ( $\text{cm}^2$ )

6 0

2 years ago

What is the product of the binomials (4a – 1) and (2b + 3)?

galben [10]

Answer:

D. 8ab+12a-2b-3

Step-by-step explanation:

You are basically combining like terms

8 0

2 years ago

Read 2 more answers

If the number of professors in a college is P and the number of students is S, and there are 19 times as many students as profes

morpeh [17]

Answer:

$S =19P\\S-19P = 0$

Step-by-step explanation:

We are given the following in the question:

Let P be the number of professor and S be the student in a college.

According to the question:

There are 19 times as many students as professors.

We have to write an equation to show the given relationship between professors and students.

$S =19P\\S-19P = 0$

The above situation is the situation that represents the given relationship.

5 0

2 years ago