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Dahasolnce [82]
3 years ago
12

Solve the following sub 1) find the value of p,ifp +5=3

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

p+5=3

or,p=3-5

or,p=-2

the value of p=-2

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Brrunno [24]

Answer:

9

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-5 - (-14)

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4 0
3 years ago
Read 2 more answers
Let f(x) = (x − 3)−2. Find all values of c in (1, 7) such that f(7) − f(1) = f '(c)(7 − 1). (Enter your answers as a comma-separ
Sidana [21]

Answer:

This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3

Step-by-step explanation:

The given function is

f(x)=(x-3)^{-2}

When we differentiate this function with respect to x, we get;

f'(x)=-\frac{2}{(x-3)^3}

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)

This implies that;

0.06-0.25=-\frac{2}{(c-3)^3} (6)

-0.19=-\frac{12}{(c-3)^3}

(c-3)^3=\frac{-12}{-0.19}

(c-3)^3=63.15789

c-3=\sqrt[3]{63.15789}

c=3+\sqrt[3]{63.15789}

c=6.98

If this function satisfies the Mean Value Theorem, then f must be continuous on  [1,7] and differentiable on (1,7).

But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.

 

3 0
3 years ago
According to a census performed in a certain country in a particular year, about 209,280,000 of it's residents were adults, and
gayaneshka [121]
54160000/209280000

= 0.2587
=25.88%
7 0
3 years ago
I need help finding the lond divison for 8÷136
nignag [31]
Let me know if you don’t understand anything. Hope this helped.

7 0
3 years ago
Which of the following is the solution set of x² + 8x + 12 = 0?
raketka [301]

Answer:

\fbox{\begin{minipage}{9em}x = -2 and x = -6\end{minipage}}

Step-by-step explanation:

Given:

x^{2} + 8x + 12 = 0

Solve for:

x

Solution:

Step 1: Select the formula to solve for x

There are some ways to solve quadratic equations.

One of the simple way (if possible) is performing the factorization.

Another way is using the quadratic formula.

Here, we are going to use factorization.

Step 2: Perform factorization

      x^{2} + 8x + 12 = 0

<=>x^{2}  +  2x + 6x  + 12 = 0

<=>(x^{2} + 2x) + (6x + 12) = 0

<=>x(x + 2) + 6(x + 2) = 0

<=>(x + 2)(x + 6) = 0

<=> x = -2 or x = -6

Hope this helps!

:)

4 0
3 years ago
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