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Dahasolnce [82]
3 years ago
12

Solve the following sub 1) find the value of p,ifp +5=3

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

p+5=3

or,p=3-5

or,p=-2

the value of p=-2

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HELP<br> what is the value of “ c”
Alex

Answer:

7

Step-by-step explanation:

When you match the form

... ax² + bx + c = 0

to the equation

... 3x² + 5x + 7 = 0

it is reasonable to conclude that ...

... a = 3, b = 5, c = 7.

_____

The question presumes you are familiar with the form

... ax² +bx +c = 0

which is often used as the representation of a general quadratic equation. This lets us use a, b, and c instead of specific numbers, to talk about ways of factoring, graphing, or solving equations like this.

6 0
3 years ago
Ashley makes 6 gallons of broth for the restaurant, she serves 30 cups of broth to guests. how many cups of soup are left over?
CaHeK987 [17]

Answer:

66 cups

Step-by-step explanation:

16 cups in 1 gallon

16*6 = 96 cups in 6 gallons

96 - 30 = 66

7 0
2 years ago
Find the indefinite integrals, if possible, using the formulas and techniques you have studied so far in the text.(a) 11 x4 dxTh
hoa [83]

Answer:

a) This integral can be evaluated using the basic integration rules. \int 11x^{4}dx = \frac{11}{5} x^{5}+C

b) This integral can be evaluated using the basic integration rules. \int 8x^{1}x^{4}dx=\frac{4}{3}x^{6}+C

c) This integral can be evaluated using the basic integration rules. \int 3x^{31}x^{4}dx=\frac{x^{36}}{12}+C

Step-by-step explanation:

a) \int 11x^{4}dx

In order to solve this problem, we can directly make use of the power rule of integration, which looks like this:

\int kx^{n}=k\frac{x^{n+1}}{n+1}+C

so in this case we would get:

\int 11x^{4}dx=11 \frac{x^{4+1}}{4+1}+C

\int 11x^{4}dx=11 \frac{x^{5}}{5}+C

b) \int 8x^{1}x^{4}dx

In order to solve this problem we just need to use some algebra to simplify it. By using power rules, we get that:

\int 8x^{1}x^{4}dx=\int 8x^{1+4}dx=\int 8x^{5}dx

So we can now use the power rule of integration:

\int 8x^{5}dx=\frac{8}{5+1}x^{5+1}+C

\int 8x^{5}dx=\frac{8}{6}x^{6}+C

\int 8x^{5}dx=\frac{4}{3}x^{6}+C

c) The same applies to this problem:

\int 3x^{31}x^{4}dx=\int 3x^{31+4}dx=\int 3x^{35}dx

and now we can use the power rule of integration:

\int 3x^{35}dx=\frac{3x^{35+1}}{35+1}+C

\int 3x^{35}dx=\frac{3x^{36}}{36}+C

\int 3x^{35}dx=\frac{x^{36}}{12}+C

6 0
3 years ago
Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| &gt; 4
nadezda [96]

Answer:

***********o                                                         o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

x>4 or x<-4

Step-by-step explanation:

You are looking for numbers that give you a distance, x, greater than 4 from 0. That wouldn't be anything between -4 and 4 because these would all give you a distance less than 4 from 0. So the answer would be to shade everything greater than 4 while also shading everything less than -4.

Here is a number line <-----|-----|-----|-----|-----|-----|-----|-----|-->

                                          -6    -4   -2    0     2     4    6    8

                                                 

Let's think about this more which of these numbers on this number line would satisfy |x|>4?

Numbers inside the numbers -4 and 4.

Or the numbers on the outside.

Let's try the inside numbers:

-2,02

|-2|>4

 2>4 is false which means -2 doesn't satisfy |x|>4

|0|>4

 0>4 is false which means 0 doesn't satisfy  |x|>4

|2|>4

 2>4 is false which means 2 doesn't satisfy  |x|>4

We could also try -4 and 4... but these will both give you a distance equal to 4 from 0.  And we are looking for greater than.

|-4|>4

 4>4 is false which mean -4 doesn't satisfy |x|>4

|4|>4

 4>4  is false which means 4 doesn't satisfy |x|>4

Now let's try the numbers on the outside:

-6,6,8

|-6|>4

 6>4 is true so -6 does satisfy |x|>4

|6|>4

 6>4 is true so 6 does satisfy |x|>4

|8|>4

 8>4 is true so 8 does satisfy |x|>4

So what I'm trying to do is convince you more that the only numbers that would satisfy |x|>4 are numbers outside the interval from -4 to 4.

So x>4 or x<-4.

On a number line the solution would look like this:

***********o                                                         o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

We have holes at -4 and 4 to mean we do not include those numbers.  We would have if the inequality read |x| \ge 4.  The line underneath this inequality means to include or equals.  We do not want to include; we did not have the equal sign.   The only difference between the two solutions would be to fill the holes if you |x| \ge 4.

4 0
2 years ago
Can you please help me?​
lozanna [386]

Answer:

7/10    70%

Step-by-step explanation:

0.7 = 7/10  0.7 x 10 = 70%

8 0
3 years ago
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