Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.
Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs
Solve for n
4n/9-n(1/5+1/4) = -3
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540
Total number of products bought
= n+n = 540+540 = 1080
Answer:
(l-3)(l+10)
Step-by-step explanation:
Applying the rule of modulus for given values, the expression will result to 20.
<h3>What is Modulus or Absolute Values</h3>
The modulus of a value for example |a|=a if a is greater than or equal to zero
and also
|a|=-a if a is less than zero
In the expression given; the modulus of -6 written as
|-6|=-(-6) this is because the value is less than zero
The modulus of 2 written as; |2|=2 this is because the value is greater than zero. and;
|The modulus of -14 written as; |-14|= -(-14) since the value is less than zero.
Hence, we can rewrite the expression as;
we deal with multiplication first following the rules of BODMAS
2×-(-6)-3×2+[-(-14)]
2×6-6+14
and thus adding values
12+14-6
and finally we subtract;
26-6
which will results to the solution of 20.
