Question

F(x)=4x^2+2x-6.find the range of function f(x).

Answer 1

Answer:

y ≥ 6.25

Step-by-step explanation:

f(x)=4x²+2x-6

positive (4) leading coefficient, curve is left up and right up

x coordinate of vertex: x = - b/2a = - 2/2*4 = - 1/4  (-0.25)

y = 4*(-1/4)² + 2*(-1/4) - 6 = -6 1/4  (-6.25)  ... extreme

range: y ≥ - 6.25    [-6.25,∞)