1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andreyy89
3 years ago
11

At the beginning of the month a store had balance og -$554 during the month

Mathematics
1 answer:
OleMash [197]3 years ago
7 0
Wheres the rest of the problem?

You might be interested in
What is the number if 50% of 25% of the number is 96
Nastasia [14]

Answer:

768

Step-by-step explanation:

because 50 percent of the num is 96 you double that and then multiply by four

3 0
2 years ago
Read 2 more answers
If x and y are both negative when is x-y positive
Vladimir [108]
X-y is positive when y is further away from 0, compared to x. In other words, when y is a larger negative

For example
x = -2
y = -5

x-y = -2-(-5) = -2+5 = 3
7 0
3 years ago
Answer to this please ?
stepan [7]

Answer:

(-a,b)

Step-by-step explanation:

You use midpoint formula which is (x1+x2/2),(y1+y2/2)

8 0
3 years ago
Kim wrote the number 11. Use mental math to tell what number has ??
Eduardwww [97]

2 more 10s then 11 is 31

1 more 10s then 11 is 21

3 more 10s then 11 is 41.

basic math :)

3 0
3 years ago
Read 2 more answers
Your friend asks if you would like to play a game of chance that uses a deck of cards and costs $1 to play. They say that if you
gtnhenbr [62]

Answer:

Expected value = 40/26 = 1.54 approximately

The player expects to win on average about $1.54 per game.

The positive expected value means it's a good idea to play the game.

============================================================

Further Explanation:

Let's label the three scenarios like so

  • scenario A: selecting a black card
  • scenario B: selecting a red card that is less than 5
  • scenario C: selecting anything that doesn't fit with the previous scenarios

The probability of scenario A happening is 1/2 because half the cards are black. Or you can notice that there are 26 black cards (13 spade + 13 club) out of 52 total, so 26/52 = 1/2. The net pay off for scenario A is 2-1 = 1 dollar because we have to account for the price to play the game.

-----------------

Now onto scenario B.

The cards that are less than five are: {A, 2, 3, 4}. I'm considering aces to be smaller than 2. There are 2 sets of these values to account for the two red suits (hearts and diamonds), meaning there are 4*2 = 8 such cards out of 52 total. Then note that 8/52 = 2/13. The probability of winning $10 is 2/13. Though the net pay off here is 10-1 = 9 dollars to account for the cost to play the game.

So far the fractions we found for scenarios A and B were: 1/2 and 2/13

Let's get each fraction to the same denominator

  • 1/2 = 13/26
  • 2/13 = 4/26

Then add them up

13/26 + 4/26 = 17/26

Next, subtract the value from 1

1 - (17/26) = 26/26 - 17/26 = 9/26

The fraction 9/26 represents the chances of getting anything other than scenario A or scenario B. The net pay off here is -1 to indicate you lose one dollar.

-----------------------------------

Here's a table to organize everything so far

\begin{array}{|c|c|c|}\cline{1-3}\text{Scenario} & \text{Probability} & \text{Net Payoff}\\ \cline{1-3}\text{A} & 1/2 & 1\\ \cline{1-3}\text{B} & 2/13 & 9\\ \cline{1-3}\text{C} & 9/26 & -1\\ \cline{1-3}\end{array}

What we do from here is multiply each probability with the corresponding net payoff. I'll write the results in the fourth column as shown below

\begin{array}{|c|c|c|c|}\cline{1-4}\text{Scenario} & \text{Probability} & \text{Net Payoff} & \text{Probability * Payoff}\\ \cline{1-4}\text{A} & 1/2 & 1 & 1/2\\ \cline{1-4}\text{B} & 2/13 & 9 & 18/13\\ \cline{1-4}\text{C} & 9/26 & -1 & -9/26\\ \cline{1-4}\end{array}

Then we add up the results of that fourth column to compute the expected value.

(1/2) + (18/13) + (-9/26)

13/26 + 36/26 - 9/26

(13+36-9)/26

40/26

1.538 approximately

This value rounds to 1.54

The expected value for the player is 1.54 which means they expect to win, on average, about $1.54 per game.

Therefore, this game is tilted in favor of the player and it's a good decision to play the game.

If the expected value was negative, then the player would lose money on average and the game wouldn't be a good idea to play (though the card dealer would be happy).

Having an expected value of 0 would indicate a mathematically fair game, as no side gains money nor do they lose money on average.

7 0
2 years ago
Other questions:
  • 2x + 3y = 3 y = 8 – 3x
    8·1 answer
  • Write 0.2 as a percentage.
    9·2 answers
  • A sample of 50 11th graders were asked to select a favorite pattern out of 6
    5·1 answer
  • Luis worked 40 hours last week and earned a total of $528. His job at Cub pays $9 per hour and
    12·1 answer
  • Find the value of x? Please help?
    11·1 answer
  • Given polynomials p, q, r, and s . q≠0 ,s≠0 and r≠0
    5·1 answer
  • For the following right triangle find the side length 19,12 x. Round the nearest hundredth
    12·1 answer
  • Is 26 a multiple of 3? yes 9r no ? why 9r why not?​
    15·2 answers
  • 5. Determine the horizontal distance when the vertical distance is 2m. You must
    10·1 answer
  • : David has saved $35 of the $140 he needs to purchase a new
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!