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2 years ago

A pair of parallel lines is cut by a transversal:

Mathematics

2 answers:

Anuta_ua [19.1K]2 years ago

6 0

55 degrees I think I may not be correct

Step2247 [10]2 years ago

3 0

さたはたはたはたはたはたはたはたはたはたしたはあらさたはたはてはありはあはあはあらありあは

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Is 1 pint eguivalent to o.473 liters

erica [24]

Why yes it is, good question

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2 years ago

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Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

Step(i):-

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

Step(ii):-

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

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2 years ago

Which polynomial is written in descending order?

Anarel [89]

The ascending or descending order of a polynomial is determined by the increasing or decreasing power of variable “x” respectively.

The question is to find about the polynomial in descending order, so in this case, the 3rd option is correct, i.e. 4x^2 – 3x + 9 or 4x^2 – 3x^1 +9x^0. The power of “x” decreasing from 2 to 1 and then finally to 0.

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2 years ago

In this excerpt the servant is a comic figure because he unknowingly invites his master

dedylja [7]

Answer:

Yes he would be

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2 years ago

PART 20 ! PLEASE HELP ALGABRA 1

34kurt

Answer:

Step-by-step explanation:

If it cost $2.05 for each hamburger that's going to be your constant.

And it says plus an additional $2,000 so you will add that after 2.05x.

And it says 13,025 is the total so that would be on the left.

13,025 = 2.05x + 2,000

I'm 100% sure

I took Honors Algebra 1 in 8th grade, so you can trust me!!!

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2 years ago

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