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viktelen [127]
3 years ago
10

Determine if the following relations are functions. if they are functions, also state the domain and range.

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

Answer:

no, they are not functions

Step-by-step explanation:

this is because a single domain has multiple range.

i.e. domain 2 has ranges 2 and 4

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For which value of x is the equation 2(1 + x) = x+3 true?<br> a.1<br> b.2 <br> c.3<br> d.4
dexar [7]

Answer:

a. 1

Step-by-step explanation:

Replace 1 with x

2 ( 1 + 1 ) = 1 + 3

2 ( 2 ) = 1 + 3

4 = 1 + 3

4 = 4

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3 years ago
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5. Find the total cost to the nearest hundredth. $12.99 T-shirt, 6% tax
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Answer:

$13.80

Step-by-step explanation:

So we start with 12.99 then we have to multiply that by 0.06 to find what we would add which is 0.7794. After this we add 12.99 with 0.7794 and it becomes 13.7694 round this to the nearest hundredth and it becomes 13.80

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55

Step-by-step explanation:

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2 years ago
What is the reference angle for 192º?​
Aleonysh [2.5K]

Answer:

78º

Step-by-step explanation:

<u>Note</u> : -

In mathematics, the reference angle is defined as the acute angle and it is measuring less than 90 degrees. It is always the smallest angle, and it makes the terminal side of an angle with the

x - axis.

<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>1</u> : -

Find where 192º lies in which quadrant.

192º lies in 3rd quadrant ( between

180º and 270º )

<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>2</u> : -

Subtract : 270 - 192

270 - 192 = 78º

( Since, 192º is greater than 180º, is subtracted from 270º )

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u> : -

78º is the reference angle for 192º.

3 0
2 years ago
What is the least common multiple of 31, 28, and 14?
WINSTONCH [101]

<u>⇨ By prime factorization method:</u>

\begin{array}{r | l}{\sf{2 & {\sf14,28,31} \\\cline{2-2} {\sf2 & {\sf7,14,31 \\\cline{2-2} {\sf7 & {\sf7,7,31 \\\cline{2-2} {\sf31 & {\sf1,1,31 \\\cline{2-2} & {\sf1,1,1\end{array}

{\sf{LCM\: = \:2 \:x\: 2 \:x\: 7 \:x\: 31}}\\\\{\sf{LCM \:= \:868}}\\}\\{\sf{Therefore,}}\\\\{\sf{LCM\:(14,\: 28,\: 31)\: = \:868

{\boxed{\sf{LCM\:=\:868}}

5 0
2 years ago
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