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kolbaska11 [484]
3 years ago
11

%20%20%5C%5C%202%29.%20%5C%3A%20%20%5Csqrt%7B12%7D%20%20-%20%20%5Csqrt%7B27%7D%20%20-%202%20%5Csqrt%7B75%7D%20%20%5C%5C%20" id="TexFormula1" title="1). \: 3 \sqrt{8} - \sqrt{50} + 2 \sqrt{18} \\ 2). \: \sqrt{12} - \sqrt{27} - 2 \sqrt{75} \\ " alt="1). \: 3 \sqrt{8} - \sqrt{50} + 2 \sqrt{18} \\ 2). \: \sqrt{12} - \sqrt{27} - 2 \sqrt{75} \\ " align="absmiddle" class="latex-formula">
Correct answer will be mark as brainliest.​
Mathematics
1 answer:
EastWind [94]3 years ago
6 0

Step-by-step explanation:

\bf 3\sqrt{8} -\sqrt{50} +2\sqrt{18} =

\bf 3\sqrt{2^{3}} -\sqrt{2\cdot5^{2}} +2\sqrt{2\cdot3^{2}} =

\bf 3\cdot 2\sqrt{2} -5\sqrt{2} +2\cdot3\sqrt{2} =

\bf 6\sqrt{2} -5\sqrt{2} +6\sqrt{2} =

\bf 12\sqrt{2} -5\sqrt{2} =\green{\underline{~7\sqrt{2}~}}

__________________

\bf \sqrt{12} -\sqrt{27} +2\sqrt{75} =

\bf \sqrt{2^{2}\cdot3} -\sqrt{3^{3}} +2\sqrt{3\cdot5^{2}} =

\bf 2\sqrt{3} -3\sqrt{3} +2\cdot5\sqrt{3} =

\bf 2\sqrt{3} -3\sqrt{3} +10\sqrt{3} =

\bf 12\sqrt{3} -3\sqrt{3}=\blue{\underline{~9\sqrt{3}~}}

==SalmonWorldTopper==

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