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Svetradugi [14.3K]
3 years ago
5

20 POINTS!!PLEASE HELP!!! At the school carnival, the sixth graders are making directional arrows, as shown

Mathematics
2 answers:
melisa1 [442]3 years ago
8 0
The area is 26 hopefully this helps you
ANTONII [103]3 years ago
8 0

Answer:

The area is 26

Step-by-step explanation:

plz give brainliest

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Which applies the power of a power rule properly to simplify the expression (710)5?
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Answer:

D;(710)5= 710 · 5 = 750

Step-by-step explanation:

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My brother is 4 years younger than my sister and 5 years older than me in 2 years. If I am 15 now how old will my sister be when
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Your sister is 24. Your brother is 20. You are 15. Therefore, your sister will be 48 years old. I’m 87% sure I did this right. Lol, good luck.
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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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3 years ago
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What’s that? Maybe I can help! When?
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2 years ago
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A school custodian discovered a leak in a water pipe. the custodian found that 1,920 fluid ounces of water had leaked out. How m
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Answer:

15 gallons

Step-by-step explanation:

Hope it helps. :)

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