1/3( 4 - 5x - 1)
= (1/3)(4 + - 5x + - 1)
= (1/3)( 4) + (1/3)(- 5x) + (1/3)( - 1)
= 4/3 + - 5x/3 + - 1/3
= - 5x/3 + 1 (Decimal: - 1.666667x + 1)
Hope that helps!!!!
Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
Answer:
2 × 2 × 3 × 5
Step-by-step explanation:
Given that,
The number = 60
To find,
Factors of 60 greater than 1 = ?
Procedure:
As we know,
Any of various numbers multiplied together to form a whole.
To find the factors of a number, we will have to do its prime factorization.
So,
The prime factorization of 60:
1 * 2 * 2 * 3 * 5 = 60
Since the factors greater than 1 are asked, the factors would be;
2 * 2 * 3 * 5
Thus, 2 * 2 * 3 * 5 is the correct answer.
Answer:
FG = 7
Step-by-step explanation:
5x+2+3x-1=9
8x+1=9
8x = 8
x = 1
FG = 5(1)+2 = 7
