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cestrela7 [59]
3 years ago
13

If k(t)=3/4t-3 what is the value of k(-12)?

Mathematics
1 answer:
Valentin [98]3 years ago
8 0

Answer:

-3.0625

Step-by-step explanation:

just plug in -12

3/4t-3

3/2(-12)-13

then solve to get -3.0625 or -3.06

and this is how you solve any problem like this.

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The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? {5, 8} {-5, -8} {3, 8} {4, 7} {4, 8}
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The range is the ouutput from inputing the input
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set to zero
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facor
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set to zer
k-7=0
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so the domain has the numbers
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3 years ago
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Answer:

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Step-by-step explanation:

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