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sdas [7]
3 years ago
13

The temperature of a cup of coffee changed by –54 degrees Celsius  over 22 ½ minutes. What was the change in temperature each mi

nute?​
Mathematics
2 answers:
Fudgin [204]3 years ago
5 0
The temperature of the cut was 22 1/1
kiruha [24]3 years ago
3 0
54/22.5=2.4 Celsius per minute
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Help me with this please everyone
cupoosta [38]
First, let's simplify each expression by combining like terms:

A: 9x-3x-4 = 6x-4

B: 12x-4 = 12x-4 (Already Combined terms)

C: 5x+x-4 = 6x-4

When looking at the list of equations, it is clear that only Expression A and C are equivalent. Brianna failed to combine like terms and plug in more points than 0. 

I Hope this Helps!
-Sinnamin

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3 years ago
The blue figure is a translation of the black image. Write a rule to describe the translation.
4vir4ik [10]

it has gone up 4 lines and left -2 making it go for a (4,-2)

5 0
3 years ago
What is 3/8 x 16/7? i don't know. it is for my math homework?
liberstina [14]
Multiply the top and bottom.

3/8 * 16/7 = 48/56

Simplified: 5/7
6 0
4 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
3 years ago
Describe the behavior of the function h around its vertical asymptote at x=-6.
steposvetlana [31]

Answer:

B

Step-by-step explanation:

One good way to look at this is to graph both polynomials, as shown in the picture. A tip to help graph is to factor it out and work from there. For example, in x²+14x+48, we can gather that (x+6)(x+8) is the same thing, and it is easier to then graph it. Similarly, for x²+12x+36, we can factor it out as (x+6)² .

When x²+12x+36 approaches 6, it is getting really close to 0, but it stays positive. When x²+14x+48 approaches 6 from the negative side, it is also getting close to 0, but it's negative. When x²+14x+48 approaches 6 from the positive side, it is positive.

Therefore, on the negative side, there is one positive and one negative (dividing a negative by a positive is negative, and a positive by a negative is also negative) , and on the positive side, there are two positives, forming one answer.The answer is therefore B

7 0
3 years ago
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