Someone please helpp meeee w this like i don’t understand

Circle the integer(s) that have an absolute value of 11

erik [133]

Answer: shouldn't it be -11?

Step-by-step explanation:

im p sure to find the AV its just like the positive version of a number. Kinda rusty since i did this a long time ago lol

3 0

3 years ago

Habiendose organizado un bingo se ha recaudado $1900. Por la entrada de hombres $15 y mujeres $10 y se ha reportado una asistenc

aev [14]

Answer:

The number of men was $80$

The number of women was $70$

Step-by-step explanation:

The question in English is

Having organized a bingo has raised $1900. For the entrance of men $15 and women $10 and an attendance of 150 people has been reported. Determine the number of men and the number of women who participated in the bingo.

Let

x----> the number of men

y----> the number of women

we know that

$x+y=150$

$x=150-y$ -----> equation A

$15x+10y=1,900$ -----> equation B

substitute equation A in equation B and solve for y

$15(150-y)+10y=1,900$

$2,250-15y+10y=1,900$

$15y-10y=2,250-1,900$

$5y=350$

$y=70$

Find the value of x

$x=150-70=80$

therefore

The number of men was $80$

The number of women was $70$

3 0

3 years ago

what is the equation, in slope- intercept form, of the line that contains the points (-3,4) and (5,7)

gavmur [86]

Answer:

y = $\frac{3}{8}$ x + $\frac{41}{8}$

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

To calculate the slope use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 4) and (x₂, y₂ ) = (5, 7)

m = $\frac{7-4}{5+3}$ = $\frac{3}{8}$ , hence

y = $\frac{3}{8}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

using (5, 7 ), then

7 = $\frac{15}{8}$ + c ⇒ c = 7 - $\frac{15}{8}$ = $\frac{41}{8}$

y = $\frac{3}{8}$ x + $\frac{41}{8}$ ← equation in slope-intercept form

6 0

3 years ago

A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th

Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

The bearing of the buoy from the is approximately 307.35°

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

$\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}$

Therefore;

$\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}$

Which gives;

$\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}$

$\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}$

Similarly, we can get;

$\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}$

The angle subtended by the distance of the buoy from the port, C is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ 307.35°

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0

2 years ago

A swimmer swam 48 kilometers in d days. What is the value of d if the averge amount swan was 3.2 kilometers?

AnnZ [28]

To find the number of days, divide the total swam by the average:

Days = 48 / 3.2 = 15

They swam for 15 days.

3 0

2 years ago