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AnnZ [28]
2 years ago
7

what fraction of a clockwise revolution does the hour of a clock turn through when it goes from a) 4 to 7 b) 8 to 2 c) 1 to 10 ​

Mathematics
1 answer:
sergiy2304 [10]2 years ago
3 0

Answer:

a) 3/12 = 1/4

b) 6/12 = 1/2

c) 9/12 = 3/4

Step-by-step explanation:

To find the distance traveled by the hour hand, subtract the beginning position from the ending position. For example, in a, the distance traveled between 4:00 and 7:00 is three hours. Since there are 12 total hours on a clock, the fraction would be 3/12 (traveled/whole revolution). Simplify further to get 1/4.

The other two problems are very similar to the explanation above. Treat the second problem's ending time as 14:00, since it is two hours after 12:00.

Hope this helps!

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2 years ago
① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method
hram777 [196]

Answer:

<h2>S = 9/20</h2><h2>J = 113/50</h2>

Step-by-step explanation:

5J +2S =12.20 ........(1)\\5J+10S=15.80......(2)\\Multiply \:equation \:(1)\:by\:the\:coefficient\:of\:x\:in equation\:(2)\\\\Multiply\:equation(2)\: by\: the\: coefficient\:of \:x\: in \:equation (1)\\\\5J +2S =12.20 ........(1) \times 5\\5J+10S=15.80......(2)\times 5\\\\25J+10S=61......(3)\\25J+50S = 79......(4)\\Subtract\:equation\:(4)\:from\: equation\: (3)\\-40S =-18\\\frac{-40S}{-40}=\frac{-18}{-40}\\  S = 9/20\\

Substitute \:9/20\:for \:x \:in\:equation\:(1)\:or \:equation\:(2)\\5J+2S = 12.20\\5J +2(9/20) =12.20\\5J +9/10=12.20\\5J=12.20-9/10\\5J=113/10\\Cross-Multiply\\50J = 113\\J = 113/50

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3 years ago
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Answer:

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Step-by-step explanation:

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